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Reptile [31]
3 years ago
15

Suresh makes 100 pieces of costume jewelry to sell to his classmates. Each piece costs him $1.55 to make. How much does it cost

Suresh to make all 100 pieces?
$0.02
$0.16
$15.50
$155.00
Mathematics
2 answers:
xeze [42]3 years ago
4 0
It costs him $155.00 to make 100 pieces
Nikitich [7]3 years ago
3 0

Answer:

$155.00

Step-by-step explanation:

$100×$1.55=$155

can i get brainliest

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What is the distance between (2,-1) and (2,5) rounded to the nearest 10th
xxMikexx [17]

Answer:

<h3>             5.0</h3>

Step-by-step explanation:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\\\d=\sqrt{(2-2)^2+(5+1)^2}=\sqrt{0^2+5^2}=\sqrt{25}=5

5 0
3 years ago
Although companies would like consumers to believe that Identity theft protection is an
stiks02 [169]

The obtained answers for the given frequency distribution are:

(a) The formula for the mean in sigma notation is \bar x =\frac{1}{n}  \sum X_i where n is the number of observations; X_i are the n observations.

The mean for the given monthly plan price is $16.1.

(b) The frequency distribution for given data is {$9.99 - 2; $10 - 5; $12 - 1; $12.75 - 2; $14.99 - 6; $20 - 4; $25 - 5}

(c) The formula for the mean using the frequency distribution table is \bar x = \frac{1}{N}\sum f_ix_i where N =\sum f_i and on applying this formula for the given data, the mean is $16.1.

(d) The median for the given data is m_e = 14.99, and the mode for the given data is $14.99

<h3>What are the mean, median, and mode for a frequency distribution?</h3>

The frequency distribution has sample observations x_i and frequencies f_i.

Then, the mean is calculated by

\bar x = \frac{1}{N}\sum f_ix_i

Where N =\sum f_i (Sum of frequencies)

The median is calculated by

m_e=\left \{ {{x_{k}} \ if \ n = 2k+1 \atop {\frac{x_{k}+x_{k+1}}{2}} \ if \ n =2k} \right.

The mode is calculated by

Mode = highest frequency value

<h3>Calculation:</h3>

The given list of data is

{$14.99, $12.75, $14.99, $14.99, $9.99, $25, $25, $10, $14.99, $10, $20, $10, $20, $14.99, $10, $25, $20, $12, $14.99, $25, $25, $20, $12.75, $10, $9.99}

(a) Formula for the mean using sigma notation and use it to calculate the mean:

The formula for the mean is

\bar x =\frac{1}{n}  \sum X_i

Where n = 25; X_i - n observations

On substituting,

Mean \bar x

=1/25(14.99+12.75+14.99+14.99+9.99+25+25+10+14.99+10+20+10+20+14.99+10+25+20+12+14.99+25+25+20+12.75+10+9.99)

= 1/25(402.42)

= 16.09 ≅ 16.1

(b) Constructing a frequency distribution for the data:

Cost - frequency - cumulative frequency

$9.99 - 2 - 2

$10 - 5 - 7

$12 - 1 - 8

$12.75 - 2 - 10

$14.99 - 6 - 16

$20 - 4 - 20

$25 - 5 - 25

Sum of frequencies N = 25;

(c) Using frequency distribution, calculating the mean:

The formula for finding the mean using frequency distribution is

\bar x = \frac{1}{N}\sum f_ix_i

Where N = 25;

On substituting,

\bar x<em> </em>= 1/25 (2 × 9.99 + 5 × 10 + 1 × 12 + 2 × 12.75 + 6 × 14.99 + 4 × 20 + 5 × 25)

  = 1/25 (402.42)

  = 16.09 ≅ 16.1

Therefore, the mean is the same as the mean obtained in option (a).

(d) Calculating the median and the mode:

Since N = 25(odd) i.e., 2· 12 + 1; k = (12 + 1)th term = 13th term

So,  the median m_e = 14.99. (frequency at 13th term)

Since the highest frequency is 6 occurred by the cost is $14.99,

Mode = 14.99

Learn more about frequency distribution here:

brainly.com/question/27820465

#SPJ9

7 0
2 years ago
Jacob leaves his summer cottage and drives home. After
krok68 [10]

Answer:

A linear relationship can be written as:

y = a*x + b

Where a is the slope and b is the y-intercept.

If this line passes through the points (a, b) and (c, d) then the slope can be written as:

a = (a - c)/(b - d)

Here y will represent the distance between Jacob and his house, and the variable x represents the time that he has ben driving.

In this case, we know that after driving for 5 hours, he is 112km from home.

Then we can write this point as (5h, 112km)

We also know that after 7 hours he is 15km from home.

Then we can write this point as (7h, 15km)

Then the slope of this function will be:

a = (15km - 112km)/(7h - 5h) = -48.5 km/h

Then the equation is:

y = -(48.5 km/h)*x + b

To find the value of b, we can replace the values of one of the points, for example in the point (7h, 15km)

This means that we need to replace x by 12h, and y by 15km, then we get:

15km = -( 48.5 km/h)*7h + b

15km + ( 48.5 km/h)*7h = b = 354.5 km

then the equation will be:

y = (-48.5 km/h)*x + 354.5 km

Now we want to answer: How long had Jacob been driving when he was 209 km from  home?

Then we need to only replace y by 209km, and solve for x:

209km = (-48.5 km/h)*x + 354.5 km

209km - 354.5 km = (-48.5 km/h)*x

-145.5km =  (-48.5 km/h)*x

-145.5km/( -48.5 km/h) = x = 3h

So he is 209km away from his home after driving for 3 hours.

6 0
3 years ago
Where do you get the 2/5 and 3/5 from
-Dominant- [34]

Answer:

we can get 3/2 as the answer

5 0
2 years ago
CAN SOMEONE HELP ME WITH THIS PROBLEM
Aliun [14]
Sorry I can’t buddy........................................................:(
4 0
3 years ago
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