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2 years ago

What is the IQR of 0,1,1,3,3,3,4,5, and 7?

Mathematics

2 answers:

pentagon [3]2 years ago

8 0

3.5 is the IQR of <span>0,1,1,3,3,3,4,5, and 7</span>

mr_godi [17]2 years ago

8 0

Answer:

3.5

Step-by-step explanation:

0, 1, 1, 3, 3, 3, 4, 5, 7

Median: 3

lower quartile: 1

upper quartile: 4.5

(IQR) interquartile range: 4.5 - 1 = 3.5

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Let p represent any number in the interval (- 18,22). Rewrite the possible values for p in inequality notation.

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Answer:

$-18 < p < 22$

Step-by-step explanation:

We are given the following information in the question.

The open interval: (- 18,22).

Let p belong to the given interval then p represents all the values belonging to the given interval.

Open Interval: An open interval is a interval that does not include the end points.

Thus, we can write:

$-18 < p < 22$

is the required inequality form required.

That is p can take values greater than -18 and smaller than 22.

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If sin square theta = 0.75, then cos =

sergeinik [125]

Answer:

$\cos\theta=\pm0.5$

Step-by-step explanation:

Given:

$\sin^2\theta=0.75$

To find $\cos\theta$

Using trigonometric relations for sums and differences of squares of the ratios.

We know:

$\sin^2\theta+\cos^2\theta =1$

Plugging in $\sin^2\theta=0.75$ in the above relation.

$0.75+\cos^2\theta =1$

Subtracting both sides by 0.75.

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Taking square root both sides.

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