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Natasha2012 [34]
4 years ago
12

which characteristic of northern renaissance artworks do albrecht dürer and pieter bruegel the elder share? a. they rarely inclu

de symbols or have hidden meanings. b. they depict landscapes instead of portraits, religious scenes, or genres. c. they show royalty instead of peasants. d. they show great attention to detail and texture. e. the figures have ideal beauty. f. the space appears flattened.
Physics
1 answer:
VladimirAG [237]4 years ago
7 0
According to my assumptions,the answer closest to the perfection is :

c. they show royalty instead of peasants.
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Approximate the field by treating the disk as a +6.1 C point charge at a distance of 21 cm Answer in units of N/C.
DaniilM [7]

Answer:

Electric field, E=1.24\times 10^{12}\ N/C

Explanation:

It is given that,

Charge, Q = +6.1 C

Distance, r = 21 cm = 0.21 m

We need to find the electric field. It is given by :

E=k\dfrac{Q}{r^2}

E=9\times 10^9\times \dfrac{6.1}{(0.21)^2}

E=1.24\times 10^{12}\ N/C

So, the electric field at this distance is 1.24\times 10^{12}\ N/C. Hence, this is the required solution.

7 0
3 years ago
How can you use a simple model to describe a wave and its features?
Volgvan

Answer:

Explanation:

Use mathematical representations to describe a simple model for waves that includes how the amplitude of a wave is related to the energy in a wave. Patterns can be used to identify cause and effect relationships.

8 0
2 years ago
Need help with 2 and 3<br>pls help, due in 1 1/2 hours<br>(GIVING 20 POINTS)​
Anarel [89]
2) acceleration = final velocity - initial velocity / time —> V-U/T
Acceleration is the change in velocity over the change in time so it can be represented by the equation a = Δv/Δt.
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7 0
3 years ago
A box is being dragged with a horizontal force of 65 N for 12 meters. If there is a force of friction acting on it
asambeis [7]

Answer:

A. 780 J

B. 120 J

C. 660 J

Explanation:

From the question given above the following data were obtained:

Dragging force (Fₔ) = 65 N

Distance (s) = 12 m

Force of friction (Fբ) = 10 N

A. Determination of the work done by the dragging force.

Dragging force (Fₔ) = 65 N

Distance (s) = 12 m

Workdone (Wd) by dragging force =?

Wd = Fₔ × s

Wd = 65 × 12

Wd = 780 J

Therefore, the work done by the dragging force is 780 J

B. Determination of the work done by friction.

Distance (s) = 12 m

Force of friction (Fբ) = 10 N

Workdone (Wd) by friction =?

Wd = Fբ × s

Wd = 10 × 12

Wd = 120 J

Therefore, the work done by friction is 120 J

C. Determination of the net work done on the box.

Dragging force (Fₔ) = 65 N

Distance (s) = 12 m

Force of friction (Fբ) = 10 N

Net work done (Wd) =?

Next, we shall determine the net force acting on the box. This can be obtained as follow:

Dragging force (Fₔ) = 65 N

Force of friction (Fբ) = 10 N

Net force (Fₙ) =?

Fₙ = Fₔ – Fբ

Fₙ = 65 – 10

Fₙ = 55 N

Thus, the net force acting on the box is 55 N

Finally, we shall determine the net work done on the box as follow:

Distance (s) = 12 m

Net force (Fₙ) = 55 N

Net work done (Wd) =?

Wd = Fₙ × s

Wd = 55 × 12

Wd = 660 J

Therefore, the net work done on the box is 660 J

4 0
3 years ago
How much work is required for a 74 kg sprinter to accelerate from rest to 2.2 m/s?
My name is Ann [436]

Answer:

179.1 kg

Explanation:

7 0
2 years ago
Read 2 more answers
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