Two students 8 meters apart are holding a stretched, coiled spring between them. One student sends a pulse down the string, and
1 answer:
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Answer:
minimum angle is 128.69°
Explanation:
given data
player velocity with respect ground v1 = 3.5 m/s
ball velocity with respect himself v2 = 5.6 m/s
to find out
smallest angle
solution
we know ball velocity with respect field will be
ball velocity = v1 +v2
ball velocity = 3.5 + 5.6 = 9.1m/s
we consider angle that player hit ball is θ
then by as per figure triangle
cosθ =
cosθ =
θ = 51.31
so minimum angle is 180 - 51.31 = 128.69°
To solve this problem we must rely on the equations of the simple harmonic movement that define the period as a function of length and gravity as
Where
l = Length
g = Gravity
Re-arrange to find L,
Our values are given as
Replacing,
Therefore the height would be 25.348m
Let be the height of the building and thus the initial height of the ball. The ball's altitude at time
is given by
where is the acceleration due to gravity.
The ball reaches the ground when after
. Solve for
:
so the building is about 16 m tall (keeping track of significant digits).