Answer:
1.Balance the equation.
2.Convert units of a given substance to moles.
3.Using the mole ratio, calculate the moles of substance yielded by the reaction.
4.Convert moles of wanted substance to desired units.
Explanation:
Answer:1 chemical reactions, 2 properties,3 substances, 4light, 5 color, 6 precipitate, 7 gas, 8 temperature
Explanation: I think this is it I did this a week ago and that’s what I remember
Board up your windows
Go to higher ground
Get food and water
The question is in complete, the complete question is:
Which element has an outer electron configuration of s
2
p4
?
(A) Ca (B) Cr (C) Ge (D) Se
Answer:
(D) Se
Explanation:
The outer electronic configuration of an atom reflects the group to which it belongs in the periodic table. Each group has its unique outermost electron configuration and number of electrons found in the outermost shell of the atoms of elements in the group.
s
2
p4 is the unique outermost electron configuration of group 16 elements. Group 16 elements have six electrons in their outermost shell. If we consider the options, only Se is a member of group 16. Hence it is only Se that has the outermost electron configuration s
2
p4
.
We are given the complete reaction:
<span>3 H2(g) + N2(g) → 2 NH3(g)</span>
First let us convert mass to moles.
moles H2 = 5.22 kg / (2 kg/kmol) = 2.61 kmol H2
moles N2 = 31.5 kg / (28 kg/kmol) = 1.125 kmol N2
Then we find for the limiting reactant. The limiting
reactant is the one who has lower (moles/coefficient) ratio.
H2 = 2.61 / 3 = 0.87
N2 = 1.125 / 1 = 1.125
Hence the H2 is the limiting reactant so we should base
the calculation of NH3 from it. We see that 2 moles of NH3 is produced for
every 3 moles of H2, therefore:
moles NH3 = 2.61 kmol H2 * (2 kmol NH3 / 3 kmol H2) = 1.74
kmol
The molar mass of NH3 is 17 kg/kmol, therefore the mass
NH3 is:
mass NH3 = 1.74 kmol * 17 kg/kmol
<span>mass NH3 = 29.58 kg</span>
