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3 years ago

Harvey is placing a microwave oven on his kitchen counter. What information does Harvey need?

Mathematics

1 answer:

vampirchik [111]3 years ago

7 0

Answer:

b the area

Step-by-step explanation:

you will need to see if you have enough area for the microwave to fit

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Jenae works at a clothing store and gets a bonus of $10 a month, plus $0.50 every time she sells the item of the month.Every tim

cluponka [151]

Answer:

$22.50

Step-by-step explanation:

Let's write what we know.

$10 a month bonus

+ $0.50 / per item of the month

$2 per compliment

We can write an equation:

T = Total bonus for the month

i = number of item of the month sales

c = number of compliments

T = $10 + $0.50i + $2c

i = 17

c = 2

Plug in the values:

T = $10 + $0.50i + $2c

T = $10 + $0.50( 17 )+ $2( 2 )

T = $10 + $8.50 + 4

T = $22.50

Her bonus for this month is $22.50

6 0

3 years ago

Determine how much the bill will be if there are 50 text messages

dolphi86 [110]

Answer:

about 105

Step-by-step explanation:

5 0

3 years ago

What is 2 and 1/2 divided into 3/4

Fed [463]

It would be 3 and 1/3

5 0

3 years ago

Read 2 more answers

Solve for r<br><br>v = 4/3 r^3<br>

sergejj [24]

Answer:

$r=\sqrt[3]{\frac{3v}{4} }$

Step-by-step explanation:

To solve for $r$ :

$v=\frac{4}{3}r^{3}$ (given)

$\frac{3v}{4}=r^{3}$ (times $\frac{3}{4}$ on both sides)

$r=\sqrt[3]{\frac{3v}{4} }$

I hope this helps :)

8 0

3 years ago

The exponential distribution applies to lifetimes of a certain component. Its failure rate is unknown. Find the probability that

wlad13 [49]

Answer:

a) 0.0821

b) 0.0111

c) 0.0041

Step-by-step explanation:

Exponential distribution:

The exponential probability distribution, with mean m, is described by the following equation:

$f(x) = \lambda e^{-\lambda x}$

In which $\lambda$ is the decay parameter.

The probability that x is lower or equal to a is given by:

$P(X \leq x) = \int\limits^a_0 {f(x)} \, dx$

Which has the following solution:

$P(X \leq x) = 1 - e^{-\lambda x}$

Either it lasts more 5 years or less, or it survives more than 5 years. The sum of the probabilities of these events is decimal 1. So

$P(X \leq 5) + P(X > 5) = 1$

In all 3 cases, we want P(X > 5). So

$P(X > 5) = 1 - P(X \leq 5)$

In which

$P(X \leq 5) = 1 - e^{-5\lambda}$

(a) lambda=.5

$P(X \leq 5) = 1 - e^{-5*0.5} = 0.9179$

$P(X > 5) = 1 - P(X \leq 5) = 1 - 0.9179 = 0.0821$

(b) lambda=0.9

$P(X \leq 5) = 1 - e^{-5*0.9} = 0.9889$

$P(X > 5) = 1 - P(X \leq 5) = 1 - 0.9889 = 0.0111$

(c) lambda=1.1

$P(X \leq 5) = 1 - e^{-5*1.1} = 0.9959$

$P(X > 5) = 1 - P(X \leq 5) = 1 - 0.9959 = 0.0041$

7 0

3 years ago