Answer:
The distance is 54.6 m
Explanation:
Given that,
Mass = 2.0 kg
Frictional coefficient = 0.21
Initial velocity = 15 m/s
We need to calculate the acceleration
Using formula of frictional force  
 
 
 
We need to calculate the acceleration
 
 
 
 
We need to calculate the initial velocity
Using equation of motion
 
Put the value  
 


Hence, The distance will be 54.6 m.
 
        
             
        
        
        
A wheely because you see when you push it it has the scwers stong
        
                    
             
        
        
        
The question is incomplete. Here is the complete question.
The image below was taken with a camera that can shoot anywhere between one and two frames per second. A continuous series of photos was combined  for this image, so the cars you see are in fact the same car, but photographed at differene times.
Let's assume that the camera was able to deliver 1.3 frames per second for this photo, and that the car has a length of approximately 5.3 meters. Using this information and the photo itself, approximately how fast did the car drive?
Answer: v = 6.5 m/s
Explanation: The question asks for velocity of the car. Velocity is given by:

The camera took 7 pictures of the car and knowing its length is 5.3, the car's displacement was:
Δx = 7(5.3)
Δx = 37.1 m
The camera delivers 1.3 frames per second and it was taken 7 photos, so time the car drove was:
1.3 frames = 1 s
7 frames = Δt
Δt = 5.4 s
Then, the car was driving:

v = 6.87 m/s
The car drove at, approximately, a velocity of 6.87 m/s 
 
        
             
        
        
        
I think the correct answer from the choices listed above is the second option. The <span> idea of plate tectonics was difficult for many scientists to accept for many years after it was first introduced because there </span><span>was no explanation yet for how it was happening. It was only to the recent times that these were proven. </span>
        
             
        
        
        
Answer:
t = 2.2 s
Explanation:
Given that,
Height of the roof, h = 24.15 m
The initial velocity of the pumpkin, u = 0
We need to find the time taken for the pumpkin to hit the ground. Let the time be t. Using second equation of kinematics to find it as follows :

Here, u = 0 and a = g

So, it will take 2.22 s for the pumpkin to hit the ground.