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tester [92]
4 years ago
14

El conductor de un coche de 650 kg que va a 90 km/h frena y reduce su

Physics
1 answer:
Ivanshal [37]4 years ago
7 0
A. 90km/h = 25 m/s
W=1/2mv^2
=1/2* 650* 25^2
= 203125(J)
b. v’= 90-50= 40km/h
= 100/9 m/s
W=1/2mv^2
=1/2*650*(100/9)^2
= 40123,45679
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Complete the equation to show the radioactive decay of carbon-14 to nitrogen-14
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Answer:

The beta decay takes place.

Explanation:

The reaction of radioactivity of carbon 14 to nitrogen 14 is

There is a beta decay.  

The reaction is

C_{6}^{14}\rightarrow N_{7}^{14}+\beta _{-1}^{0}+ energy

Here some energy is released in form of neutrino.

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3 years ago
Y=mx+b if y=8.18 m=1.31 b=17.2 then find x
Dafna1 [17]

Plug in the corresponding values into y = mx + b

8.18 in for y

1.31 in for m

17.2 in for b

8.18 = 1.31x + 17.2

Now bring 17.2 to the left side by subtracting 17.2 to both sides (what you do on one side you must do to the other). Since 17.2 is being added on the right side, subtraction (the opposite of addition) will cancel it out (make it zero) from the right side and bring it over to the left side.

8.18 - 17.2 = 1.31x

-9.02 = 1.31x

Then divide 1.31 to both sides to isolate x. Since 1.31 is being multiplied by x, division (the opposite of multiplication) will cancel 1.31 out (in this case it will make 1.31 one) from the right side and bring it over to the left side.

-9.02/1.31 = 1.31x/1.31

x ≈ -6.8855

x is roughly -6.89

Hope this helped!

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8 0
4 years ago
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According to Newton's third law of motion, if you push against a wall, the wall will __________.
slavikrds [6]

Answer:

push up agaisnt you with equal force.

3 0
3 years ago
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A gravitational _____ exists between you and every object in the universe.
andrew-mc [135]
A pair of equal gravitational forces ... one in each direction ...
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We start with 5.00 moles of an ideal monatomic gas with an initial temperature of 128 ∘C. The gas expands and, in the process, a
o-na [289]

Answer:

The final temperature of the gas is <em>114.53°C</em>.

Explanation:

Firstly, we calculate the change in internal energy, ΔU from the first law of thermodynamics:

ΔU=Q - W

ΔU = 1180 J - 2020 J = -840 J

Secondly, from the ideal gas law, we calculate the final temperature of the gas, using the change in internal energy:

ΔU=\frac{3}{2} nRΔT

ΔU=\frac{3}{2} nR(T_{2} -T_{1} )

Then we make the final temperature, T₂, subject of the formula:

T_{2} =\frac{2ΔU}{3nR} +T_{1}

T_{2} =\frac{2(-840J)}{(3)(5)(8.314J/mol.K)} +128 deg.C

T_{2} =114.53 deg.C

Therefore the final temperature of the gas, T₂, is 114.53°C.

7 0
4 years ago
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