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tester [92]
3 years ago
14

El conductor de un coche de 650 kg que va a 90 km/h frena y reduce su

Physics
1 answer:
Ivanshal [37]3 years ago
7 0
A. 90km/h = 25 m/s
W=1/2mv^2
=1/2* 650* 25^2
= 203125(J)
b. v’= 90-50= 40km/h
= 100/9 m/s
W=1/2mv^2
=1/2*650*(100/9)^2
= 40123,45679
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Light with energy equal to three times the work function of a given metal causes the metal to eject photoelectrons. What is the
Mrac [35]

The ratio of the maximum photoelectron kinetic energy to the work function will be 3:1.

<h3 /><h3>What is the photoelectric effect?</h3>

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The emission of ions from a steel plate when light falls on it is a common definition of the effect. The substance could be a solid, liquid, or gas; and the released particles could be protons or electrons.

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1 year ago
Which of the following are NATURAL resources? Which of the following are NATURAL resources? Select all that apply.
scoundrel [369]
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4 0
3 years ago
Read 2 more answers
Desperado, a roller coaster built in Nevada, has a mass of 800 kg. It also has a vertical drop of 225 feet down the first hill.
weeeeeb [17]

Answer:

the work done by friction on the car is 524,582 J.

Explanation:

Given;

mass of the roller coaster, m = 800 kg

distance moved by the coaster, d = 225 ft = 68.58 m

final velocity of the coaster, v = 80 mi/h = 35.76 m/s

The time taken for the coaster to drop down the hill is calculated as;

t = \sqrt{\frac{2h}{g} } \\\\t = \sqrt{\frac{2\ \times \ 68.58}{9.8} } \\\\t = 3.74 \ s

The work done by friction on the car is calculated as;

W =F\ \times \ d = \frac{mv}{t} \times \ d\\\\W = \frac{800 \ \times \ 35.76  }{3.74} \times \ 68.58\\\\W = 524,582 \ J

Therefore, the work done by friction on the car is 524,582 J.

6 0
3 years ago
Pweese help luvs qwq<br> pweese look at the image?
hjlf

Answer:

12 m/s

Explanation:

divide distance over time

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3 years ago
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