Answer:
In physics, work is the amount of energy required to perform a given task (such as moving an object from one point to another). We start by defining the scalar product of two vectors, which is an integral part of the definition of work, and then turn to defining and using the concept of work to solve problems.
Answer:
no it is not correct dimensionally
Explanation:
f=1/l√T/m
taking square on both side in order to remove square root
f²=T/l²m
f=ma =kgm/sec²
therefore
kg.m/sec²=sec/m².kg
kg.m=sec*sec²/m².kg
kg.m=sec³/m².kg
kg=sec³/m³.kg
so the equation is incorrect dimensionally
I believe thye answer is either d or c
<span>It is important to use a fixed common reference point on your work peace or drawing to avoid cumulative error</span>
