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lara31 [8.8K]
3 years ago
15

The half-reaction at the cathode in an electrochemical cell is given below.

Chemistry
1 answer:
olga55 [171]3 years ago
7 0

Explanation:

a) Anode:  

Cathode :  

b)  

c) As  , the reaction is spontaneous.

d)  

Explanation:

a) Here Ni undergoes oxidation by loss of electrons, thus act as anode. Hydrogen undergoes reduction by gain of electrons and thus act as cathode.

Anode:  

Cathode :  

b) The representation is given by writing the anode on left hand side followed by its ion with its molar concentration. It is followed by a slat bridge. Then the cathodic ion with its molar concentration is written and then the cathode.

c)  

Where both  are standard reduction potentials.

= +ve, reaction is spontaneous

= -ve, reaction is non spontaneous

= 0, reaction is in equilibrium

Thus as  , the reaction is spontaneous.

d) The standard emf of a cell is related to Gibbs free energy by following relation:

= standard gibbs free energy

n= no of electrons gained or lost

F= faraday's constant

= standard emf

Thus value of Gibbs free energy is -48250 Joules.

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PIT_PIT [208]

i believe it would be B '' tetrahedral compound ''

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3 years ago
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Alchemists in the Middle Ages dreamed of converting base metals, such as lead, into precious metals—gold and silver. Why could t
lesantik [10]

Explanation:

Each element in the periodic table has different but fixed number of the protons in nucleus of it's atom, which is known as the atomic number.

Transmutation of one chemical element into the another involves the changing of the atomic number. Such nuclear reaction requires millions of the times more energy as compared to normal chemical reactions. Thus, the dream of  the alchemist of transmuting the lead into the gold was never achievable chemically .

Conversion of lead to gold in today's world:

This conversion is indeed possible. The requirements are a particle accelerator, tremendous supply of the energy. Nuclear scientists at the Lawrence Berkeley National Laboratory located in California, more than 30 years ago, succeeded in producing very minute amounts of the gold from the bismuth. Bismuth is a metallic element which is adjacent to the lead on periodic table. Same process would work for the lead but isolating gold at end of reaction would prove much more difficult because lead is available in many isotopes. The homogeneous nature of the element means that it is easier to separate the gold from the bismuth as compared to separate the gold from the lead which has four  isotopic identities which all are stable.

4 0
3 years ago
Write the chemical equation that represents the process of lattice energy for the case of nacl.
faust18 [17]

Answer: Na^+(g)+Cl^-(g)\rightarrow NaCl(s),\Delta H_{Lattice}=-786kJ/mol

Explanation:

Lattice energy : It is defined energy released when ions combine together in a gaseous phase to form a compound. it is energy possessed by the crystal lattice of a compound. Denoted by symbol \Delta H_{Lattice}.

\Delta H_{Lattice}=positive , energy is absorbed while forming of the lattice

\Delta H_{Lattice}=negative, energy is release while forming of the lattice

Na^+(g)+Cl^-(g)\rightarrow NaCl(s),\Delta H_{Lattice}=-786kJ/mol

One mole of sodium ion when combines with one mole chloride ion release  786 kJ of energy.

4 0
3 years ago
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What is the molarity of a solution containing 56 grams of LiF in 959 mL of solution?
andrezito [222]

Answer:

2.25 M     <========= I do not see this in your selection of answers !

Explanation:

Mole weight of  Li F

      ( from periodic table ) = 6.94 + 18.998  = 25.938 gm/mole

56 gm / ( 25.938 gm /mole) = 2.15899 moles

2.15899 mole / (.959) L = 2.25 M

7 0
1 year ago
How many grams of C are required to react with 97.1 g of Fe2O3?
sashaice [31]

Answer:

21.9 g C

Explanation:

Fe₂O₃  +  3 C  ⇒  2 Fe  +  3 CO

This is your chemical equation.  

To find the grams of C required, first convert grams of Fe₂O₃ to moles using the molar mass (159.69 g/mol).  

(97.1 g)/(159.69 g/mol) = 0.608 mol Fe₂O₃

Then, use the mole ratio between Fe₂O₃ and C to convert moles of Fe₂O₃ to moles of C.  You can find the mole ratio by looking at the chemical equation.

(0.608 mol Fe₂O₃) × (3 mol Fe₂O₃/1 mol Fe₂O₃) = 1.824 mol C

You can then convert moles of C to grams using the molar mass (12.01 g/mol).

(1.824 mol) × (12.01 g/mol) = 21.9 g

5 0
3 years ago
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