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lara31 [8.8K]
3 years ago
15

The half-reaction at the cathode in an electrochemical cell is given below.

Chemistry
1 answer:
olga55 [171]3 years ago
7 0

Explanation:

a) Anode:  

Cathode :  

b)  

c) As  , the reaction is spontaneous.

d)  

Explanation:

a) Here Ni undergoes oxidation by loss of electrons, thus act as anode. Hydrogen undergoes reduction by gain of electrons and thus act as cathode.

Anode:  

Cathode :  

b) The representation is given by writing the anode on left hand side followed by its ion with its molar concentration. It is followed by a slat bridge. Then the cathodic ion with its molar concentration is written and then the cathode.

c)  

Where both  are standard reduction potentials.

= +ve, reaction is spontaneous

= -ve, reaction is non spontaneous

= 0, reaction is in equilibrium

Thus as  , the reaction is spontaneous.

d) The standard emf of a cell is related to Gibbs free energy by following relation:

= standard gibbs free energy

n= no of electrons gained or lost

F= faraday's constant

= standard emf

Thus value of Gibbs free energy is -48250 Joules.

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Explanation:

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4 0
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Explanation:

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Explanation:

FORMULA

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-----------------------------------

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Hope this helps!! :)

Please let me know if you have any question

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