Answer:
The answer to your question is letter d
Explanation:
If we remember there is a limit of electrons that can be place in a sublevel
Sublevel s only accept 2 electrons
Sublevel p only accept 6 electrons
Sublevel d only accept 10 electrons
Sublevel f only accept 14 electrons
This is in agreement wth the levels of energy, that only accept a determine number of electrons
Level Sublevel # of electrons
1 s 2
2 s and p 8 (2 + 6)
3 s, p and d 18 (2+6+10)
4 s, p, d, f 32 (2+6+10+14)
5 s, p, d,f 32 (2+6+10+14)
6 s, p, d 18 (2+6+10)
7 s, p 8 (2+6)
Answer:
0.93 mol
Explanation:
Given data:
Number of moles of Na atom = ?
Number of atoms = 5.60× 10²³
Solution:
Avogadro number:
The given problem will solve by using Avogadro number.
It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.
The number 6.022 × 10²³ is called Avogadro number.
1 mole = 6.022 × 10²³ atoms
5.60× 10²³ atoms × 1 mol / 6.022 × 10²³ atoms
0.93 mol
1 mole --------- 22.4 ( at STP )
2.66 moles ---- ?
V = 2. 66 * 22.4 / 1
V = 59.584 / 1
V = 59.584 L
hope this helps!
<span>The law of conservation of mass applies to all chemical reaction, so this means that there was equal mass before and after the reaction. However, if the mass has decreased, then it means there has been a loss of substance. The most common cause of this is the liberation of gases from a chemical reaction mixture, the mass of which is not measured by the scale.</span>
Hello!
A) H<span>ow many grams of hydrogen are necessary to react completely with 50.0g of nitrogen in the above reaction?
The balanced chemical reaction is the following one:
N</span>
₂(g) + 3H₂(g) → 2NH₃(g)To calculate the amount of hydrogen necessary we will use the following conversion factor to go from grams of nitrogen to grams of hydrogen:

So, 10,7950
grams of H₂ are required to react with 50 g of nitrogen
<span>B) How many grams of ammonia are produced in the reaction from the previous problem?
</span>The balanced chemical reaction again is the following one:
N₂ + 3H₂ → 2NH₃To calculate the amount of ammonia produced we will use the following conversion factor to go from grams of nitrogen to grams of ammonia:

So, 60,7968
grams of NH₃ are produced from 50 g of nitrogen
C) <span>How many grams of silver chloride are produced from 5.0g of silver nitrate reacting with an excess of barium chloride?
The balanced chemical equation for the reaction is the following one:
2AgNO</span>
₃ + BaCl₂ → 2AgCl + Ba(NO₃)₂
To calculate the mass of Silver Chloride produced we will use the following conversion factor to go from grams of Silver Nitrate to grams of Silver Chloride:

So,
4,219 g of AgCl are produced from the reaction of 5 g of AgNO₃
D) <span>How much barium chloride is necessary to react with the silver nitrate in the previous problem?
</span>The balanced chemical equation for the reaction is the following one:
2AgNO₃ + BaCl₂ → 2AgCl + Ba(NO₃)₂
To calculate the mass of Barium Chloride necessary we will use the following conversion factor to go from grams of Silver Nitrate to grams of Barium Chloride:

So,
3,08 g of BaCl₂ are produced from the reaction of 5 g of AgNO₃
Have a nice day!