What is Not considered as metric system ? a. Length b. Mass c. Time d. Volume e. Temperature
2 answers:
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Answer:
7.15
Explanation:
Firstly, the COP of such heat pump must be measured that is,
Therefore, the temperature relationship,
Then, we should apply the values in the COP.
The number of heat rejected by the heat pump must then be calculated.
We must then calculate the refrigerant mass flow rate.
The value is 145.27 and therefore the hot reservoir temperature is 64° C.
The pressure at 64 ° C is thus 1849.36 kPa by interpolation.
And, the lowest reservoir temperature must be calculated.
the lowest reservoir temperature = 258.703 kpa
So, the pressure ratio should be = 7.15
Answer:
The volume of the gas is 11.2 L.
Explanation:
Initially, we have:
V₁ = 700.0 L
P₁ = 760.0 mmHg = 1 atm
T₁ = 100.0 °C
When the gas is in the thank we have:
V₂ =?
P₂ = 20.0 atm
T₂ = 32.0 °C
Now, we can find the volume of the gas in the thank by using the Ideal Gas Law:
(1)
Where R is the gas constant
With the initials conditions we can find the number of moles:
(2)
By entering equation (2) into (1) we have:
Therefore, When the gas is placed into a tank the volume of the gas is 11.2 L.
I hope it helps you!
Answer: 93.30kg
Explanation:
in the attachment
