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2 years ago

Please Help! B belongs to AC D belongs to lineAF

Mathematics

1 answer:

Anvisha [2.4K]2 years ago

5 0

Answer:

x = 27

Step-by-step explanation:

∠ CAD and ∠ EDF are corresponding angles and are congruent, so

∠ CAD = 2x

The sum of the 3 angles in Δ ABD = 180°

sum the angles and equate to 180

72 + 2x + 2x = 180

72 + 4x = 180 ( subtract 72 from both sides )

4x = 108 ( divide both sides by 4 )

x = 27

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Evaluate 8 times 6+(12-4)%2

Rudik [331]

Answer:

I'm going to assume that the percentage sign means divide.

Step-by-step explanation:

8*6+(12-4)/2

8*6+(8)/2

48+8/2

48+4

6 0

2 years ago

BRAINLIEST!!!

goldenfox [79]

Answer: $\frac{8}{17}$ or 8:17

Step-by-step explanation:

For any angle x (other than right angle) in a right triangle ,the trigonometric ratio of sin x is given by :-

$\sin x=\frac{\text{side opposite to x}}{\text{Hypotenuse}}$

Given: A right triangle with hypotenuse = 68 units

The side adjacent to S = 60

Let h be the side opposite to S, then using Pythagoras in the given right triangle, we get

$(68)^2=60^2+h^2\\\\\Rightarrow\ h^2=68^2-60^2\\\\\Rightarrow\ h^2=1024\\\\\Rightarrow\ h=\sqrt{1024}=32$

Thus, the side opposite to S = 32 units

Now, the trigonometric ratio for sin S is given by :-

$\sin S=\frac{\text{side opposite to S}}{\text{Hypotenuse}}\\\\\Rightarrow\sin S=\frac{32}{68}=\frac{8}{17}$

Hence, the trigonometric ratio for sin S = $\frac{8}{17}$ or 8:17

5 0

2 years ago

find the centre and radius of the following Cycles 9 x square + 9 y square +27 x + 12 y + 19 equals 0

Citrus2011 [14]

Answer:

Radius: $r =\frac{\sqrt {21}}{6}$

$Center = (-\frac{3}{2}, -\frac{2}{3})$

Step-by-step explanation:

Given

$9x^2 + 9y^2 + 27x + 12y + 19 = 0$

Solving (a): The radius of the circle

First, we express the equation as:

$(x - h)^2 + (y - k)^2 = r^2$

Where

$r = radius$

$(h,k) =center$

So, we have:

$9x^2 + 9y^2 + 27x + 12y + 19 = 0$

Divide through by 9

$x^2 + y^2 + 3x + \frac{12}{9}y + \frac{19}{9} = 0$

Rewrite as:

$x^2 + 3x + y^2+ \frac{12}{9}y =- \frac{19}{9}$

Group the expression into 2

$[x^2 + 3x] + [y^2+ \frac{12}{9}y] =- \frac{19}{9}$

$[x^2 + 3x] + [y^2+ \frac{4}{3}y] =- \frac{19}{9}$

Next, we complete the square on each group.

For $[x^2 + 3x]$

1: Divide the $coefficient\ of\ x\ by\ 2$

2: Take the $square\ of\ the\ division$

3: Add this $square\ to\ both\ sides\ of\ the\ equation.$

So, we have:

$[x^2 + 3x] + [y^2+ \frac{4}{3}y] =- \frac{19}{9}$

$[x^2 + 3x + (\frac{3}{2})^2] + [y^2+ \frac{4}{3}y] =- \frac{19}{9}+ (\frac{3}{2})^2$

Factorize

$[x + \frac{3}{2}]^2+ [y^2+ \frac{4}{3}y] =- \frac{19}{9}+ (\frac{3}{2})^2$

Apply the same to y

$[x + \frac{3}{2}]^2+ [y^2+ \frac{4}{3}y +(\frac{4}{6})^2 ] =- \frac{19}{9}+ (\frac{3}{2})^2 +(\frac{4}{6})^2$

$[x + \frac{3}{2}]^2+ [y +\frac{4}{6}]^2 =- \frac{19}{9}+ (\frac{3}{2})^2 +(\frac{4}{6})^2$

$[x + \frac{3}{2}]^2+ [y +\frac{4}{6}]^2 =- \frac{19}{9}+ \frac{9}{4} +\frac{16}{36}$

Add the fractions

$[x + \frac{3}{2}]^2+ [y +\frac{4}{6}]^2 =\frac{-19 * 4 + 9 * 9 + 16 * 1}{36}$

$[x + \frac{3}{2}]^2+ [y +\frac{4}{6}]^2 =\frac{21}{36}$

$[x + \frac{3}{2}]^2+ [y +\frac{4}{6}]^2 =\frac{7}{12}$

$[x + \frac{3}{2}]^2+ [y +\frac{2}{3}]^2 =\frac{7}{12}$

Recall that:

$(x - h)^2 + (y - k)^2 = r^2$

By comparison:

$r^2 =\frac{7}{12}$

Take square roots of both sides

$r =\sqrt{\frac{7}{12}}$

Split

$r =\frac{\sqrt 7}{\sqrt 12}$

Rationalize

$r =\frac{\sqrt 7*\sqrt 12}{\sqrt 12*\sqrt 12}$

$r =\frac{\sqrt {84}}{12}$

$r =\frac{\sqrt {4*21}}{12}$

$r =\frac{2\sqrt {21}}{12}$

$r =\frac{\sqrt {21}}{6}$

Solving (b): The center

Recall that:

$(x - h)^2 + (y - k)^2 = r^2$

Where

$r = radius$

$(h,k) =center$

From:

$[x + \frac{3}{2}]^2+ [y +\frac{2}{3}]^2 =\frac{7}{12}$

$-h = \frac{3}{2}$ and $-k = \frac{2}{3}$

Solve for h and k

$h = -\frac{3}{2}$ and $k = -\frac{2}{3}$

Hence, the center is:

$Center = (-\frac{3}{2}, -\frac{2}{3})$

6 0

2 years ago

En la casa de Juan, van a pedir pizza para la comida, pero cuando la van a pedir se dan cuenta que deben pedirla por perímetro o

Degger [83]

Responder:

La pizza con un perímetro de 100 cm es más grande ¿verdad?

Explicación paso a paso:

Deja que la pizza tenga forma circular.

Sea el área de la pizza = πd² / 4 y;

Perímetro de la pizza = πd

d es el diámetro de la pizza

Si la madre dice que el que tiene un perímetro de 100 cm es más grande, para estar seguros necesitamos obtener el diámetro de la pizza. La de mayor diámetro será la pizza más grande.

P = 100cm

100 = πd

d = 100 / π

d = 100 / 3,14

d = 31,85 cm

El diámetro de la pizza mamá es de 31,85 cm.

Si el padre dice que el que tiene un área de 100 cm² es más grande, obtengamos también el diámetro para estar seguros.

A = πd² / 4

100 = πd² / 4

400 = πd²

d² = 400 / π

d² = 400 / 3,14

d² = 127,39

d = √127,39

d = 11,29 cm

Por lo tanto, el diámetro de la pizza padre es de 11,29 cm.

Dado que el diámetro de la pizza madre es mayor que el de esa, la pizza con un perímetro de 100 cm es más grande, lo que demuestra que la madre tiene razón.

6 0

2 years ago

Of the following points, name all that lie on the same horizontal line?

ArbitrLikvidat [17]

I just graphed all 4 and didn’t see where any are on the same horizontal line. I might be missing something.

7 0

2 years ago