Answer:
a
When peter held the book for one minute the rate at which motor unites are fired increase steeply but as the duration increases the increese in the rate at which it is being fired becomes linear so the number of activated motors stay the same but are being activated at a more rapidly
b
The same motors are activated whilest he is hold the book for 2 minutes this is because for peter to hold the book in one fixed position one specific motor units need to be activated
Note changing the motor unites would change the positon of the hand
Explanation:
Answer:

Explanation:
<u>Constant Acceleration Motion</u>
It's a type of motion in which the velocity of an object changes uniformly in time.
Being a the constant acceleration, vo the initial speed, vf the final speed, and t the time, the following relation applies:

The car initially travels at vo=7.35 m/s and accelerates at a rate of
during t=2.09 s.
The final velocity is:


Answer:
The right answer is "1.369 m/s²".
Explanation:
The given values are:
Distance (s)
= 260 m
Initial speed (u)
= 26 m/s
Reaction time (t')
= 0.51 s
During reaction time, the distance travelled by locomotive will be:
⇒ 


Remained distance between locomotive and car:
⇒ 


Now,
The final velocity to avoid collection is, V = 0 m/s
From third equation of motion:
⇒ 
On putting the estimated values, we get
⇒ 
⇒ 
⇒ 
⇒ 
⇒ 
They are experiencing the pull of leaving the atmosphere