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worty [1.4K]
3 years ago
12

Help asap please!!!!​

Physics
1 answer:
lara [203]3 years ago
8 0

Answer:

true is correct answer answer

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A person riding in a hot air air balloon basket ascends to 1000 ft above the ground. What happened to the atmospheric pressure a
kherson [118]
C) it decreased
because atmospheric pressure decreases as we move up.
8 0
3 years ago
It is known that the gravitational force of attraction between two alpha particles is much weaker than the electrical repulsion.
natali 33 [55]

Answer:

<em>The ratio of gravitational force to electrical force is 3.19 x 10^-36 </em>

<em></em>

Explanation:

mass of an alpha particle = 6.64 x 10^{-27} kg

charge on an alpha particle = +2e = +2(1.6 x 10^{-19} C) = 3.2 x 10^{-19} C

distance between particles = d

For gravitational attraction:

The force of gravitational attraction F = \frac{Gm^{2} }{r^{2} }

where G = gravitational constant = 6.67 x 10^{-11} m^3 kg^-1 s^-2

r = the distance between the particles = d

m = the mass of each particle

therefore, gravitational force = \frac{6.67*10^{-11}*(6.64*10^{-27} )^{2}  }{d^{2} } = \frac{2.94*10^{-63} }{d^{2} }  Newton

For electrical repulsion:

Electrical force between the particles = \frac{-kQ^{2} }{r^{2} }

where k is the Coulomb's constant = 9.0 x 10^{9} N•m^2/C^2

r = distance between the particles = d

Q = charge on each particle

therefore, electrical force = \frac{-9*10^{9}*(3.2*10^{-19} )^{2}  }{d^{2} } = \frac{-9.216*10^{-28} }{d^{2} } Newton

the negative sign implies that there is a repulsion on the particles due to their like charges.

Ratio of the magnitude of gravitation to electrical force = \frac{2.94*10^{-63} }{9.216*10^{-28} }

==> <em>3.19 x 10^-36 </em>

8 0
2 years ago
A car travels 100 m while decelerating to 8 m/s in 5 s.<br> a) What was its initial speed?
viktelen [127]

Answer:

Vi = 32 [m/s]

Explanation:

In order to solve this problem we must use the following the two following kinematics equations.

v_{f} =v_{i} - (a*t)\\

The negative sign of the second term of the equation means that the velocity decreases, as indicated in the problem.

where:

Vf = final velocity = 8[m/s]

Vi = initial velocity [m/s]

a = acceleration = [m/s^2]

t = time = 5 [s]

Now replacing:

8 = Vi - 5*a

Vi = (8 + 5*a)

As we can see we have two unknowns the initial velocity and the acceleration, so we must use a second kinematics equation.

v_{f}^{2} = v_{i}^{2} - (2*a*d)

where:

d = distance = 100[m]

(8^2) = (8 + 5*a)^2 - (2*a*100)

64 = (64 + 80*a + 25*a^2) - 200*a

0 = 80*a - 200*a + 25*a^2

0 = - 120*a + 25*a^2

0 = 25*a(a - 4.8)

therefore:

a = 0 or a = 4.8 [m/s^2]

We choose the value of 4.8 as the acceleration value, since the zero value would not apply.

Returning to the first equation:

8 = Vi - (4.8*5)

Vi = 32 [m/s]

6 0
3 years ago
According to gay-lussac’s law: select one:
DaniilM [7]
Gay-Lussac's Law states
P1 / T1 = P2 / T2
So the answer is b

8 0
3 years ago
Read 2 more answers
If the distance d (in meters) traveled by an object in time t (in seconds) is given by the formula d=a+bt2, the si units of a an
ss7ja [257]
Distance , d = a+bt^2

The unit of d is in meter and t is in seconds.

So the unit of a a must be meter.

Now we have unit of bt^2 is meter.

So unit of b*second^2 = meter

Unit of b = meter/second^2

So unit of a = m and unit of b = m/s^2.
8 0
2 years ago
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