Answer:
ummm I think the answer is Carrot
Answer:
<em>There are approximately 114 rabbits in the year 10</em>
Step-by-step explanation:
<u>Exponential Growth
</u>
The natural growth of some magnitudes can be modeled by the equation:

Where P is the actual amount of the magnitude, Po is its initial amount, r is the growth rate and t is the time.
We are given two measurements of the population of rabbits on an island.
In year 1, there are 50 rabbits. This is the point (1,50)
In year 5, there are 72 rabbits. This is the point (5,72)
Substituting in the general model, we have:

![50=P_o(1+r)\qquad\qquad[1]](https://tex.z-dn.net/?f=50%3DP_o%281%2Br%29%5Cqquad%5Cqquad%5B1%5D)
![72=P_o(1+r)^5\qquad\qquad[2]](https://tex.z-dn.net/?f=72%3DP_o%281%2Br%29%5E5%5Cqquad%5Cqquad%5B2%5D)
Dividing [2] by [1]:

Solving for r:
![\displaystyle r=\sqrt[4]{\frac{72}{50}}-1](https://tex.z-dn.net/?f=%5Cdisplaystyle%20r%3D%5Csqrt%5B4%5D%7B%5Cfrac%7B72%7D%7B50%7D%7D-1)
Calculating:
r=0.095445
From [1], solve for Po:



The model can be written now as:

In year t=10, the population of rabbits is:

P = 113.6

There are approximately 114 rabbits in the year 10
Expression B results in a positive number
Cheerios
Answer:
just give me a like
Step-by-step explanation:
just click the heart and click on the 5th star thanks
39/50= 0.78 times 100= 78
78 is Donovan's score
if maci's score is 10 percentage points higher
78+10=88
x /50 =0.88 times 100= 88
x=44
each question is 2 points: 88-78= 10/2=5
Maci answered 5 questions correctly.