Answer:
the answer is A
Step-by-step explanation:
the Pythagorean theorem is a squared + b squared = c squared (c always being the hypotenuse and a and b being the legs. 2 (4) squared pus 10 (100) squared=104 then you would use the square root of 104. 104 does not have a whole number square so the answer is 
I believe C. Measuring the length from one end of the field tot he other would be the most reasonable answer, because Area = Length x Width
Answer:
Smallest possible length of the hypotenuse = 65
Step-by-step explanation:
Given - A right angle triangle has sides whose lengths are $2$-digit integers. The digits of the length of the hypotenuse are the reverse of the digits of the length of one of the other sides.
To find - Determine the smallest possible length of the hypotenuse.
Proof -
The possible Pythagoras triplets of a right angled triangle with 2 digit integers are -
(11, 60, 61)
(12, 35, 34)
(13, 84, 85)
(16, 63, 65)
(20, 21, 29)
(28, 45, 53)
(33, 56, 65)
( 36, 77, 85)
(39, 80, 89)
(48, 55, 73)
(65, 72, 97)
But, Here Given that
The digits of the length of the hypotenuse are the reverse of the digits of the length of one of the other sides.
So, There is only one possibility that satisfy the condition.
and that is, (33, 56, 65)
So, we get
Length of one side = 33
Length of second side = 56
Length of hypotenuse = 65
So,
Smallest possible length of the hypotenuse = 65
Answer:
QT = 45
Step-by-step explanation:
ST = 65
SP = 26
RQ = 30
QT = 4x - 3
Given that ∆STR is similar to ∆PTQ, therefore:
Plug in the values
Solve for x
Cross multiply
Collect like terms
Divide both sides by 8
✅QT = 4x - 3
Plug in the value of x
QT = 4(12) - 3 = 48 - 3
QT = 45
