1 answer:
Answer:
The specific heat of air is 100 J/kg°C.
Explanation:
mass, m = 5 kg
Temperature change, T' - T = 37 °C - 22 °C = 15°C
heat, H = 7500 J
let the specific heat of air is c.
The formula of heat is
H = m c (T' - T)
7500 = 5 x c x 15
c = 100 J/kg°C
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