According to Newton's Third Law, the magnitude of the reaction by the nail will be - 200 N. The correct answer is option B
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Newton's Third Law of Motion</h3>
Newton's Third Law of motion states that in any action on an object or on a body, there will be equal and opposite reaction by the body.
If a hammer puts a force of 200 N on a nail, according to Newton's Third Law, the nail will put back on the hammer an equal but opposite force. That is,
The action on the nail = 200 N
The reaction by the nail = - 200 N
Therefore, the nail will put back on the hammer a force of - 200 N
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A. 4% you divide 2000 to 500 and you get 4 which is your answer
Explanation:
It is given that,
Length of the poster, l = 0.95 m
Breadth of the poster, b = 1 m
The poster is in the shape of rectangle. For a rectangular shape, perimeter is equal to :
P = 2(l+b)
P=2(0.95+1)
P=3.9 m
(b) One digits, P = 4 m
(c) Two digits, P = 3.9 m
(d) Three digits, P = 3.90 m
For this question, we use the Coulumb's law to calculate the force on each particles. In this law, force between point charges are said to be proportional to product of each charge and is indirectly proportional to the distance of both charges. We do as follows:
F= kq(1)q(2)/d^2
= (9x10^9).(1.41 x 10^-5 C).(-<span>1.41 x 10^-5 C</span><span>)/.44^2
</span> = 4.067 N