Yo sup??
magnitude of original vector is 5 units.
angle made with x axis is 67°
horizontal component=5*cos67°
=5*0.4
=2 units (approx)
Therefore the correct answer is option B
Hope this helps
The answer is a rainforest I’m pretty sure
Answer with Explanation:
We are given that
Diameter of pipe,![d_1=0.573 m](https://tex.z-dn.net/?f=d_1%3D0.573%20m)
![v_1=13.5 m/s](https://tex.z-dn.net/?f=v_1%3D13.5%20m%2Fs)
![v_2=5.83 m/s](https://tex.z-dn.net/?f=v_2%3D5.83%20m%2Fs)
Volume flow rate of the petroleum along the pipe=![Q_{refinery}=A_1v_1=v_(\frac{\pi d^2_1}{4})](https://tex.z-dn.net/?f=Q_%7Brefinery%7D%3DA_1v_1%3Dv_%28%5Cfrac%7B%5Cpi%20d%5E2_1%7D%7B4%7D%29)
![Q_{refinery}=13.5\times (\pi\times \frac{0.573)^2}{4})=3.48 m^3/s](https://tex.z-dn.net/?f=Q_%7Brefinery%7D%3D13.5%5Ctimes%20%28%5Cpi%5Ctimes%20%5Cfrac%7B0.573%29%5E2%7D%7B4%7D%29%3D3.48%20m%5E3%2Fs)
By equation of continuity
![A_1v_1=A_2v_2](https://tex.z-dn.net/?f=A_1v_1%3DA_2v_2)
![\frac{\pi d^2_1}{4}v_1=\frac{\pi d^2_2}{4}v_2](https://tex.z-dn.net/?f=%5Cfrac%7B%5Cpi%20d%5E2_1%7D%7B4%7Dv_1%3D%5Cfrac%7B%5Cpi%20d%5E2_2%7D%7B4%7Dv_2)
![d^2_2=\frac{v_1}{v_2}d^2_1](https://tex.z-dn.net/?f=d%5E2_2%3D%5Cfrac%7Bv_1%7D%7Bv_2%7Dd%5E2_1)
![d_2=\sqrt{\frac{v_1}{v_2}}d_1](https://tex.z-dn.net/?f=d_2%3D%5Csqrt%7B%5Cfrac%7Bv_1%7D%7Bv_2%7D%7Dd_1)
![d_2=0.573\sqrt{\frac{13.5}{5.83}}](https://tex.z-dn.net/?f=d_2%3D0.573%5Csqrt%7B%5Cfrac%7B13.5%7D%7B5.83%7D%7D)
![d_2=0.87 m](https://tex.z-dn.net/?f=d_2%3D0.87%20m)
![d_2=0.87\time 100=87 cm](https://tex.z-dn.net/?f=d_2%3D0.87%5Ctime%20100%3D87%20cm)
1 m=100 cm