Which of the following best represents an isolated system?

What factors determine electric potential?

NNADVOKAT [17]

Answer: C. Charge and distance

4 0

3 years ago

A straight, cylindrical wire lying along the x axis has a length L and a diameter d . It is made of a material described by Ohm'

Zepler [3.9K]

The magnitude and direction of the electric field in the wire are mathematically given as

$L &=[(v / L) v / m] \hat{i}$

<h3>What is the magnitude and direction of the electric field in the wire?</h3>

Generally, the equation for is mathematically given as

A cylindrical wire that is straight and parallel to the x-axis has the following dimensions: length L, diameter d, resistivity p, diameter d, potential v, and z length. combining elements from both sides

E d $x=\int d v.$

$\begin{aligned}&-E \int_0^L d x=\int_v^0 d v \\\therefore E \cdot L &=v \\L &=[(v / L) v / m] \hat{i}\end{aligned}$

In conclusion, the magnitude and direction of the electric field in the wire are given as

$L &=[(v / L) v / m]$

Read more about electric fields

brainly.com/question/15800304

#SPJ4

7 0

2 years ago

Three children are riding on the edge of a merry‑go‑round that has a mass of 105 kg105 kg and a radius of 1.80 m1.80 m . The mer

rewona [7]

Answer:

New angular speed changes from 16 rpm to 19.95 rpm

Explanation:

In the given system the angular momentum of the system is conserved

initial angular momentum of the system

$L_{i}=I_{1}\omega _{1}\\\\\omega _{1}=\frac{8\pi }{15}rad/sec\\\\I_{1}=\frac{1}{2}mr^{2}+(m_{1}+m_{2}+m_{3})r^{2}\\\\I_{1}=\frac{1}{2}\times 105\times 1.8^{2}+(33+28+28) \times 1.8^{2}=458.46kgm^{2}\\\\\therefore L_{i}=458.46\times \frac{8\pi }{15}=768.16$

When 28 kg child moves to the center the moment of inertia changes thus we have

$I_{2}=\frac{1}{2}mr^{2}+(m_{1}+m_{2})r^{2}\\\\I_{1}=\frac{1}{2}\times 105\times 1.8^{2}+(33+28) \times 1.8^{2}=367.74kgm^{2}\\\\\therefore L_{f}=367.74\times \omega _{f}$

Equating initial and final angular momentum we get

$I_{2}=\frac{1}{2}mr^{2}+(m_{1}+m_{2})r^{2}\\\\I_{1}=\frac{1}{2}\times 105\times 1.8^{2}+(33+28) \times 1.8^{2}=367.74kgm^{2}\\\\\therefore L_{f}=367.74\times \omega _{f}\\\\\omega _{f}=\frac{768.16}{367.74}=2.1rad/sec\\\\N_{2}=19.95rpm$

7 0

3 years ago

The unit of capacitance is the farad (F).

Arte-miy333 [17]

Answer:

C/V

Explanation:

Mathematically it is known that one farad is defined as the capacitance across which, when charged with one coulomb, there is a potential difference of one volt. In other words, the Farad is Coulomb/Volt or C/V

4 0

4 years ago

Emily is pushing a toy sand truck. She realizes it is much harder to push the truck when it is full of sand than when it is empt

irga5000 [103]

Answer: An object with a greater mass requires a greater force to accelerate.

Explanation:

3 0

3 years ago