Answer:
The median level in the water is 7ppm
Explanation:
LoB is assessed by calculating duplicates of a blank sample and evaluating the mean result and the standard deviation (SD). After evaluating this value LOD can be evaluated conferring to LOD=LOB+1.645(SD low concentration sample ). The quantitation limit can also be got from accuracy studies. LOD's may also be evaluated based on the standard deviation of the response (Sy) of the curve and the slope of the calibration curve (S) at levels resembling the LOD according to the formula: LOD = 3.3
Answer:
Empirical formula: BH3
Molecular Formula: B2H6
Explanation:
To solve the exercise, we need to know how many boron atoms and how many hydrogen atoms the compound has. We know that of the total weight of the compound, 78.14% correspond to boron and 21.86% to hydrogen. As the weight of the compound is between 27 g and 28 g, using the above percentages we can solve that the compound has between 21.1 g and 21.8 g of boron, and between 5.9 g and 6.1 g of hydrogen:
100% _____ 27 g
78.14% _____ x = 78.14% * 27g / 100% = 21.1 g boron
100% ______27 g
21.86% ______ x = 21.86% * 27g / 100% = 5.9 g hydrogen
100% _____ 28 g
78.14% _____ x = 78.14% * 28g / 100% = 21.8 g boron
100% _____ 28g
21.86% _____ x = 21.86% * 28g / 100% = 6.1 g hydrogen
So, if the atomic weight of boron is 10.8 g, there must be two boron atoms in the compound that sum 21.6 g. The weight of hydrogen is 1 g, so the compound must have six hydrogen atoms.
The molecular formula represents the real amount of atoms that form a compound. Therefore, the molecular formula of the compound is B2H6.
The empirical formula is the minimum expression that represents the proportion of atoms in a compound. For example, ethane has 2 carbon atoms and 6 hydrogen atoms, so its molecular formula is C2H6, however, its empirical formula is CH3. Therefore, the empirical formula of the boron compound is BH3.
Answer:
The red blood cells will burst
Explanation:
When the red blood cells are placed in pure water, they will gain water by osmosis, swell and finally burst due to their weak cell membranes. This process is referred to as hemolysis.
balance by putting 2 next to HF
Answer:
Three possible blood type alleles are Iᴬ, Iᴮ and i
Explanation:
Iᴬ, Iᴮ and i are three possible blood type alleles.
Iᴬ and Iᴮ are known as co-dominant, and The i allele is recessive.
Thus, Three possible blood type alleles are Iᴬ, Iᴮ and i
<u>-TheUnknownScientist</u>
