Answer:
Explanation: A yellow precipitate o lead iodide is formed. see equation of reaction below: 
→ 
Th PbI2 is the insoluble yellow precipitate
Electrolytes are substances that produce ions when they dissolve in water.
What are electrolytes?
When some substances are dissolved in water, they undergo physical or chemical changes, creating ions in solution. These substances form an important class of compounds called electrolytes. Substances that do not release ions when dissolved are called non-electrolytes. A substance is said to be a strong electrolyte if the physical or chemical process that produces ions is inherently 100% efficient (all dissolved compounds produce ions). A solute is said to be a weak electrolyte if only a relatively small portion of the solute undergoes ion production processes.
By measuring the electrical conductivity of aqueous solutions containing substances, substances can be identified as strong, weak, or non-electrolyte. To conduct electricity, a substance must contain free-moving charged species. The best known is the conduction of electricity through metal wires. In this case, the mobile charged unit is the electron.
Therefore, Electrolytes are substances that produce ions when they dissolve in water.
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The statement is true in this situation is C. The size of Ffric is the same as the size of Fapp:
From the diagram, since the body is in equilibrium, the sum of vertical forces equals zero. Also, the sum of horizontal forces equal zero.
So, ∑Fx = 0 and ∑Fy = 0
Since Fapp acts in the negative x - direction and Ffric acts in the positive x - direction,
∑Fx = -Fapp + Ffric = 0
-Fapp + Ffric = 0
Fapp = Ffric
Also, since Fgrav acts in the negative y - direction and Fnorm acts in the positive y - direction,
∑Fy = Fnorm + (-Fgrav) = 0
Fnorm - Fgrav = 0
Fnorm = Fgrav
So, we see that the size of Fapp <u>equals</u> size of Ffric and the size of Fnorm <u>equals</u> the size of Fgrav.
So, the correct option is C
The statement which is true in this situation is C. The size of Ffric is the same as the size of Fapp.
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