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Rashid [163]
2 years ago
10

The chemical equation of rusting of iron is given

Chemistry
1 answer:
artcher [175]2 years ago
6 0

Answer:

{ \tt{(a). { \bf{reactants : { \tt{iron \:  and \: oxygen}}}}}} \\ { \bf{products :  { \tt{iron(iii)oxide}}}} \\  \\ { \tt{(b).}} \: { \bf{1.204 \times  {10}^{24}  \: atoms}} \\ { \tt{(c).}} \: { \tt{4Fe +3 O _{2}  → 2Fe _{2}O _{3}}} \\  \\ { \underline{ \blue{ \tt{becker \: jnr}}}}

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The normal freezing point of a certain liquid
slavikrds [6]

Answer : The molal freezing point depression constant of liquid X is, 4.12^oC/m

Explanation :  Given,

Mass of urea (solute) = 5.90 g

Mass of liquid X (solvent) = 450 g  = 0.450 kg

Molar mass of urea = 60 g/mole

Formula used :  

\Delta T_f=i\times K_f\times m\\\\T^o-T_s=i\times K_f\times\frac{\text{Mass of urea}}{\text{Molar mass of urea}\times \text{Mass of liquid X Kg}}

where,

\Delta T_f = change in freezing point

\Delta T_s = freezing point of solution = -0.5^oC

\Delta T^o = freezing point of liquid X = 0.4^oC

i = Van't Hoff factor = 1 (for non-electrolyte)

K_f = Molal-freezing-point-depression constant = ?

m = molality

Now put all the given values in this formula, we get

0.4^oC-(-0.5^oC)=1\times K_f\times \frac{5.90g}{60g/mol\times 0.450kg}

K_f=4.12^oC/m

Therefore, the molal freezing point depression constant of liquid X is, 4.12^oC/m

3 0
3 years ago
For which of the following will the entropy of the system increase?
snow_lady [41]

Answer :  The correct option is, (d) sublimation of dry ice.

Explanation :

Entropy : It is defined as the measurement of randomness or disorderedness in a system.

The order of entropy will be,

As we are moving from solid state to liquid state to gaseous state, the entropy will be increases due to the increase in the disorderedness.

As we are moving from gaseous state to liquid state to solid state, the entropy will be decreases due to the decrease in the disorderedness.

(a) Condensation of steam.

Condensation : It is a type of process in which the phase changes from gaseous state to liquid state at constant temperature.

In this process, phase changes from gaseous state to liquid state that means the degree of disorderedness decreases. So, the entropy will also decreases.

(b) Reaction of magnesium with oxygen to form magnesium oxide.

Mg(s)+O_2(g)\rightarrow MgO(s)

In this reaction, the randomness of reactant molecules are more (solid+gas) and as we move towards the formation of product the randomness become less (solid) that means the degree of disorderedness decreases. So, the entropy will also decreases.

(d) Reaction of nitrogen and hydrogen to form ammonia.

N_2(g)+H_2(g)\rightarrow NH_3(g)

In this reaction, the randomness of reactant molecules are more (2 moles of gas) and as we move towards the formation of product the randomness become less (1 mole of gas) that means the degree of disorderedness decreases. So, the entropy will also decreases.

(d) Sublimation of dry ice.

Sublimation : It is a type of process in which the phase changes from solid state to gaseous state without passing through the liquid state at constant temperature.

In this process, phase changes from solid state to gaseous state that means the degree of disorderedness increases. So, the entropy will also increases.

3 0
3 years ago
What is the mass in grams of 0.0015 mol of aspirin (C9H8O4)
almond37 [142]

Answer:

116.1 g

Explanation:

3 0
2 years ago
Read 2 more answers
The lighted half of the moon faces away from Earth during the _____ moon phase.
shtirl [24]
The lighted half of the moon faces away from the earth during the New Moon phase
3 0
3 years ago
Valence Bond theory predicts that tin will use what hybrid orbitals in Snf5 -1​
LUCKY_DIMON [66]

Answer:

sp3d

Explanation:

The ground state electronic configuration of tin is written as; [Kr] 5s²4d¹⁰5p². Hybridization is a concept used to explain the combination of orbitals of appropriate energy to produce suitable orbitals that could be used for bonding.

In forming the compound Snf5^ -1, we have to hybridize the following orbitals on tin; 5p, 5d and 6s orbitals. This gives us a set of sp3d hybrid  hence the answer.

6 0
2 years ago
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