Answer:
N₂(g) + 4H⁺(aq) + 4e⁻ → N₂H₄(aq)
Explanation:
The half reaction for the reaction for the reduction of gaseous nitrogen to aqueous hydrazine is;
N₂(g) → N₂H₄(aq)
The balancing the atoms in the half reaction. Hydrogen atom is balanced by adding hydrogen ions (H⁺)
We have;
N₂(g) + 4H⁺(aq) → N₂H₄(aq)
Then we balance the charge on both sides by adding electrons where the positive charge is greater;
we have;
N₂(g) + 4H⁺(aq) + 4e⁻ → N₂H₄(aq)
I believe your answer will be 40
Answer:
725L
Explanation:
From the question given, we obtained the following information:
V1 = 274L
P1 = 133kPa
T1 = 316k
P2 = 98kPa
T2 = 616K
V2 =?
We can obtain the new volume by doing the following:
P1V1/T1 = P2V2/T2
133 x 274 / 316 = 98x V2 / 616
Cross multiply to express in linear form:
316 x 98 x V2 = 133 x 274 x 616
Divide both side by 316 x 98
V2 = ( 133 x 274 x 616) /316 x 98
V2 = 725L
Therefore, the new volume is 725L
