<h3>Answer:</h3>
388.94 g N₂
<h3>General Formulas and Concepts:</h3><u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
- Left to Right
<u>Chemistry</u>
<u>Atomic Structure</u>
- Reading a Periodic Table
- Using Stoichiometry
<u>Step 1: Define</u>
[RxN] 4HCl (g) + 6NO (g) → 5N₂ (g) + 6H₂O (g)
[Given] 404.87 g HCl
<u>Step 2: Identify Conversions</u>
[RxN] 4 mol HCl = 5 mol N₂
Molar Mass of H - 1.01 g/mol
Molar Mass of Cl - 35.45 g/mol
Molar Mass of HCl - 1.01 + 35.45 = 36.46 g/mol
Molar Mass of N - 14.01 g/mol
Molar Mass of N₂ - 2(14.01) = 28.02 g/mol
<u>Step 3: Stoichiometry</u>
<u /> = 388.935 g N₂
<u>Step 4: Check</u>
<em>We are given 5 sig figs. Follow sig fig rules and round.</em>
388.935 g N₂ ≈ 388.94 g N₂