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3 years ago

WILL GIVE BRAINLIEST IF YOU EXPLAIN (this is 7th grade Science / Chemistry btw):

Chemistry

2 answers:

alekssr [168]3 years ago

8 0

Answer:

2 chlorine atoms.

Explanation:

H₂ + Cl₂ → 2HCl

The Law of Conservation of Mass states that matter can neither be created nor destroyed in a chemical reaction.

If 2 molecules of Hydrogen and 2 molecules of Chlorine is present in the reactants, the same no. of atoms should also be present in the product.

∴ the no. of chlorine atoms in the product is 2.

melamori03 [73]3 years ago

3 0

I don’t know this sorry

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Explain how you know that no new element with an atomic number less than 100 will be discovered

Klio2033 [76]

The elements are identified by its aomic number and they are placed in the periodic table in ascending order of atomic number.

There is one unique element for a given atomic number.

For example, atomic number 1 identifies Hydrogen and there cannot be another different element with the same atomic number.

All the elements with atomic numbers from 1 to 118 have been discovered. So, you know that there is not room for new products with atomic number equal or less than 118.

3 0

3 years ago

How many electrons can occupy the 4p sub level of a neutral atom of bromine?

natita [175]

Answer:

five electrons

Bromine (Z=35), which has 35 electrons, can be found in Period 4, Group VII of the periodic table. Since bromine has 7 valence electrons, the 4s orbital will be completely filled with 2 electrons, and the remaining five electrons will occupy the 4p orbital

5 0

3 years ago

Read 2 more answers

Which one of the following pairs of acids and conjugate bases is incorrectly labeled or incorrectly matched? Acid Conjugate Base

vekshin1

Answer : The incorrect option is, (d) $NH_4^+/NH_2^-$

Explanation :

According to the Bronsted Lowry concept, Bronsted Lowry-acid is a substance that donates one or more hydrogen ion in a reaction and Bronsted Lowry-base is a substance that accepts one or more hydrogen ion in a reaction.

Or we can say that, conjugate acid is proton donor and conjugate base is proton acceptor.

(a) The equilibrium reaction will be,

$HF+H_2O\rightleftharpoons F^-+H_3O^+$

In this reaction, $HF$ is an acid that donate a proton or hydrogen to $H_2O$ base and it forms $F^-$ and $H_3O^+$ are conjugate base and acid respectively.

In this reaction, $HF/F^-$ are act as a conjugate acid-base.

(b) The equilibrium reaction will be,

$HClO+H_2O\rightleftharpoons ClO^-+H_3O^+$

In this reaction, $HClO$ is an acid that donate a proton or hydrogen to $H_2O$ base and it forms $ClO^-$ and $H_3O^+$ are conjugate base and acid respectively.

In this reaction, $HClO/ClO^-$ are act as a conjugate acid-base.

(c) The equilibrium reaction will be,

$H_2O+H_2O\rightleftharpoons OH^-+H_3O^+$

In this reaction, $H_2O$ is an acid that donate a proton or hydrogen to

In this reaction, $H_2O/OH^-$ are act as a conjugate acid-base.

(d) The equilibrium reaction will be,

$NH_4^++H_2O\rightleftharpoons NH_3+H_3O^+$

In this reaction, $NH_4^+$ is an acid that donate a proton or hydrogen to $H_2O$ base and it forms $NH_3$ and $H_3O^+$ are conjugate base and acid respectively.

In this reaction, $NH_4^+/NH_3$ are act as a conjugate acid-base.

(e) The equilibrium reaction will be,

$H_3O^++H_2O\rightleftharpoons H_2O+H_3O^+$

In this reaction, $H_3O^+$ is an acid that donate a proton or hydrogen to $H_2O$ base and it forms

In this reaction, $H_3O^+/H_2O$ are act as a conjugate acid-base.

From this we conclude that that, $NH_4^+/NH_2^-$ pairs of acids and conjugate bases is incorrectly labeled or incorrectly matched.

Hence, the incorrect option is, (d) $NH_4^+/NH_2^-$

4 0

3 years ago

What's the difference between series and parallel circuit in table form?

schepotkina [342]

Hey :)

In a parallel circuit, a different amount of current flows through each parallel branch of the circuit.

In the series circuit, different voltage exists across each component in the circuit.

Whereas in the parallel circuit, the same voltage exists across the multiple components in the circuit.

Hope this helps :)

5 0

4 years ago

Read 2 more answers

You mix 265.0 mL of 1.20 M lead(II) nitrate with 293 mL of 1.55 M potassium iodide. The lead(II) iodide is insoluble. What amoun

slava [35]

Answer:

105 grams PbI₂

Explanation:

Pb(NO₃)₂ + 2KI => 2KNO₃ + PbI₂(s)

moles Pb(NO₃)₂ = 0.265L(1.2M) = 0.318 mole

moles KI = 0.293(1.55M) = 0.454 mole => Limiting Reactant

moles PbI₂ from mole KI in excess Pb(NO₃)₂ = 1/2(0.454 mole) = 0.227 mol PbI₂

grams PbI₂ = 0.227 mol PbI₂ x 461 g/mole = 104.68 g ≈ 105 g PbI₂(s)

7 0

3 years ago

Read 2 more answers