All categories

3 years ago

A sample of an uranium compound is found to be losing mass gradually. Explain what is happening to the sample.

Chemistry

1 answer:

yan [13]3 years ago

4 0

Answer:

The uranium in the sample of the compound is radioactive

Explanation:

Some atoms can split on their own. Some split when bombarded by energetic particles. Such atoms are said to be radioactive.

Radioactivity is borne out of the drive of an atom to reach stabillity. Every atom have a specific neutron/proton ratio which ensures stability of the nucleus. A nucleus with a stability ratio different from that which makes it stable will become unstable and split into one or more other nuclei with emissons of energetic particles.

Note: neutrons and protons dictates the mass of an atom. They are located in the nucleus which is the site for nuclear radioactive reactions.

You might be interested in

When a mercury-202 nucleus is bombarded with a neutron, a proton is ejected. What element is formed?

Galina-37 [17]

That will make a gold-202 nucleus.

<h3>Explanation</h3>

Refer to a periodic table. The atomic number of mercury Hg is 80.

Step One: Bombard the $\displaystyle ^{202}_{\phantom{2}80}\text{Hg}$ with a neutron $^{1}_{0}n$ . The neutron will add 1 to the mass number 202 of $^{202}_{\phantom{2}80}\text{Hg}$ . However, the atomic number will stay the same.

New mass number: 202 + 1 = 203.
Atomic number is still 80.

$^{202}_{\phantom{2}80}\text{Hg} + ^{1}_{0}n \to ^{203}_{\phantom{2}80}\text{Hg}$ .

Double check the equation:

Sum of mass number on the left-hand side = 202 + 1 = 203 = Sum of mass number on the right-hand side.
Sum of atomic number on the left-hand side = 80 = Sum of atomic number on the right-hand side.

Step Two: The $^{203}_{\phantom{2}80}\text{Hg}$ nucleus loses a proton $^{1}_{1}p$ . Both the mass number 203 and the atomic number will decrease by 1.

New mass number: 203 - 1 = 202.
New atomic number: 80 - 1 = 79.

Refer to a periodic table. What's the element with atomic number 79? Gold Au.

$^{203}_{\phantom{2}80}\text{Hg} \to ^{202}_{\phantom{2}79}\text{Au} + ^{1}_{1}p$ .

Double check the equation:

Sum of mass number on the left-hand side = 203 = 202 + 1 = Sum of mass number on the right-hand side.
Sum of atomic number on the left-hand side = 80 = 79 + 1 = Sum of atomic number on the right-hand side.

A gold-202 nucleus is formed.

6 0

3 years ago

Which of these elements exist as a liquid at normal Earth temperatures? Select all that apply. bromine sodium oxygen mercury

Anni [7]

Mercury exist as liquid at normal earth tempertures

4 0

2 years ago

Read 2 more answers

What is the formula for the ionic compound made up of the ions Cd+3 and SO4-2?

Tems11 [23]

Answer: since the sodium ion is Na+, and sulfate is SO4(2-), you'll need 2 sodiums for a sulfate, making sodium sulfate Na2SO4.

Explanation:

7 0

2 years ago

How many Earths will we need to have enough resources if the whole world lived like Americans?

Oxana [17]

Answer:

2749274826186482737216657574758757863352`1`12345678998546897786544785786445082796468578967109878378610978378517629865378632749274826186482737216657574758757863352`1`12345678998546897786544785786445082796468578967109878378610978378517629865378632749274826186482737216657574758757863352`1`12345678998546897786544785786445082796468578967109878378610978378517629865378632749274826186482737216657574758757863352`1`12345678998546897786544785786445082796468578967109878378610978378517629865378632749274826186482737216657574758757863352`1`12345678998546897786544785786445082796468578967109878378610978378517629865378632749274826186482737216657574758757863352`1`12345678998546897786544785786445082796468578967109878378610978378517629865378632749274826186482737216657574758757863352`1`12345678998546897786544785786445082796468578967109878378610978378517629865378632749274826186482737216657574758757863352`1`12345678998546897786544785786445082796468578967109878378610978378517629865378632749274826186482737216657574758757863352`1`12345678998546897786544785786445082796468578967109878378610978378517629865378632749274826186482737216657574758757863352`1`12345678998546897786544785786445082796468578967109878378610978378517629865378632749274826186482737216657574758757863352`1`12345678998546897786544785786445082796468578967109878378610978378517629865378632749274826186482737216657574758757863352`1`12345678998546897786544785786445082796468578967109878378610978378517629865378632749274826186482737216657574758757863352`1`12345678998546897786544785786445082796468578967109878378610978378517629865378632749274826186482737216657574758757863352`1`12345678998546897786544785786445082796468578967109878378610978378517629865378632749274826186482737216657574758757863352`1`12345678998546897786544785786445082796468578967109878378610978378517629865378632749274826186482737216657574758757863352`1`12345678998546897786544785786445082796468578967109878378610978378517629865378632749274826186482737216657574758757863352`1`12345678998546897786544785786445082796468578967109878378610978378517629865378632749274826186482737216657574758757863352`1`12345678998546897786544785786445082796468578967109878378610978378517629865378632749274826186482737216657574758757863352`1`12345678998546897786544785786445082796468578967109878378610978378517629865378632749274826186482737216657574758757863352`1`12345678998546897786544785786445082796468578967109878378610978378517629865378632749274826186482737216657574758757863352`1`12345678998546897786544785786445082796468578967109878378610978378517629865378632749274826186482737216657574758757863352`1`12345678998546897786544785786445082796468578967109878378610978378517629865378632749274826186482737216657574758757863352`1`12345678998546897786544785786445082796468578967109878378610978378517629865378632749274826186482737216657574758757863352`1`12345678998546897786544785786445082796468578967109878378610978378517629865378632749274826186482737216657574758757863352`1`12345678998546897786544785786445082796468578967109878378610978378517629865378632749274826186482737216657574758757863352`1`12345678998546897786544785786445082796468578967109878378610978378517629865378632749274826186482737216657574758757863352`1`12345678998546897786544785786445082796468578967109878378610978378517629865378632749274826186482737216657574758757863352`1`12345678998546897786544785786445082796468578967109878378610978378517629865378632749274826186482737216657574758757863352`1`12345678998546897786544785786445082796468578967109878378610978378517629865378632749274826186482737216657574758757863352`1`12345678998546897786544785786445082796468578967109878378610978378517629865378632749274826186482737216657574758757863352`1`12345678998546897786544785786445082796468578967109878378610978378517629865378632749274826186482737216657574758757863352`1`1234567899854689778654478578644508279646857896710987837861097837851762986537863 earths

Explanation:

because yeah

4 0

3 years ago

Read 2 more answers

When 4.50 L of hydrogen gas react with an excess of nitrogen gas at standard temperature and pressure, how many liters of ammoni

VARVARA [1.3K]

Answer:

3.0 L of NH₃

Solution:

The equation is as follow,

N₂ + 3 H₂ → 2 NH₃

According to equation,

67.2 L (3 mole) H₂ at STP produces = 44.8 L (3 mole) of NH₃

So,

4.50 L of H₂ will produce = X L of NH₃

Solving for X,

X = (4.50 L × 44.8 L) ÷ 67.2 L

X = 3.0 L of NH₃

5 0

3 years ago

A sample of an uranium compound is found to be losing mass gradually. Explain what is happening to the sample.​

A sample of an uranium compound is found to be losing mass gradually. Explain what is happening to the sample.