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Zanzabum
2 years ago
8

A uniform magnetic field passes through a horizontal circular wire loop at an angle 15.1° from the normal to the plane of the lo

op. The magnitude of the magnetic field is 3.35 T , and the radius of the wire loop is 0.240 m . Find the magnetic flux Φ through the loop.
Physics
1 answer:
Zepler [3.9K]2 years ago
5 0

Answer:

0.5849Weber

Explanation:

The formula for calculating the magnetic flus is expressed as:

\phi = BAcos \theta

Given

The magnitude of the magnetic field B = 3.35T

Area of the loop = πr² = 3.14(0.24)² = 0.180864m²

angle of the wire loop θ = 15.1°

Substitute the given values into the formula:

\phi = 3.35(0.180864)cos15.1^0\\\phi =0.6058944cos15.1^0\\\phi =0.6058944(0.9655)\\\phi = 0.5849Wb

Hence the magnetic flux Φ through the loop is 0.5849Weber

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Explicación:

Paso uno:

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