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abruzzese [7]
3 years ago
15

A girl pulls a sled with a force of 15 N over a distance of 3 m. What is the kinetic energy of the sled after she pulls it? Assu

me there is no friction.
Physics
2 answers:
docker41 [41]3 years ago
5 0

Answer:

Kinetic energy, KE = 45 J

Explanation:

It is given that,

Force applied by girl on a sled, F = 15 N

It moves a distance, d = 3 m

We need to find the kinetic energy of the sled after she pulls it. We know that the work done is equal to the change in kinetic energy

W=\Delta E=K_f-K_i

K_i=0 (initial at rest)

KE=W=F\times d

KE=15\ N\times 3\ m=45\ J

So, the kinetic energy of the sled after she pulls it is 45 J. Hence, this is the required solution.

Ivenika [448]3 years ago
3 0
The answer is 45 because you multiply 15 x 3 
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harina [27]
     Let us consider the air with the index 1 and the lucite with index 2. Using the Snell's Secound Law, we have:

\frac{sen\O_{2}}{sen\O_{1}} = \frac{n_{2}}{n_{1}} \\ sen\O_{2}= \frac{n_{2}*sen\O_{1}}{n_{1}}
 
     Entering the unknowns, remembering that the air refrective index is 1 and the lucite refrective index is 1.5, comes:

sen\O_{2}= \frac{n_{2}*sen\O_{1}}{n_{1}} \\ sen\O_{2}= \frac{1.5* \frac{1}{2} }{1} \\ sen\O_{2}=0.75
  
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sen\O_{2}=0.75 \\ arcsin(0.75)=\O_{2} \\ \boxed {\O_{2}=48.59^o}

Obs: Approximate results, and the drawing is attached

If you notice any mistake in my english, let me know, because i am not native.

6 0
3 years ago
2. Using a giant screw, a crew does 650 J of work to drill a hole into a rock.
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Ork is done if a boat has a force 60N and travels 600 meters
Travka [436]

Answer:

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3 0
2 years ago
You place a small air cart on a 4.00 m air track and set it into motion with a speed of 0.75 m/s. Due to very good elastic bumpe
san4es73 [151]

Answer:

6 seconds

0.167 Hz

Explanation:

Distance = 4 m

Velocity = 0.75 m/s

Period is given by

T=2\times Distance\times Velocity\\\Rightarrow T=2\times 4\times 0.75\\\Rightarrow T=6\ s

The period of the motion is 3 seconds

Frequency is given by

f=\frac{1}{T}\\\Rightarrow f=\frac{1}{6}\\\Rightarrow f=0.167\ Hz

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3 years ago
A ping-pong ball is shot straight north from a popgun at 4.0 m/s. The wind is blowing to the west at 3.0 m/s. What is the actual
Vlad1618 [11]

Actual velocity of the ping-pong ball= 5 m/s

Explanation:

velocity of ping pong ball because of the shot gun= 4 m/s North

velocity added to the ping-pong ball due to the wind=3 m/s

These velocities are perpendicular to each other. so we use Pythagoras theorem to find the resultant velocity of the ping- pong ball

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V= √25

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5 0
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