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abruzzese [7]
3 years ago
15

A girl pulls a sled with a force of 15 N over a distance of 3 m. What is the kinetic energy of the sled after she pulls it? Assu

me there is no friction.
Physics
2 answers:
docker41 [41]3 years ago
5 0

Answer:

Kinetic energy, KE = 45 J

Explanation:

It is given that,

Force applied by girl on a sled, F = 15 N

It moves a distance, d = 3 m

We need to find the kinetic energy of the sled after she pulls it. We know that the work done is equal to the change in kinetic energy

W=\Delta E=K_f-K_i

K_i=0 (initial at rest)

KE=W=F\times d

KE=15\ N\times 3\ m=45\ J

So, the kinetic energy of the sled after she pulls it is 45 J. Hence, this is the required solution.

Ivenika [448]3 years ago
3 0
The answer is 45 because you multiply 15 x 3 
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Radio waves travel at a speed of 300,000,000 m/s. WFNX broadcasts radio waves at a
yKpoI14uk [10]

Answer:

Wavelength, \lambda=2.94\ m

Explanation:

It is given that,

Speed of radio waves is v=3\times 10^8\ m/s

Frequency of radio waves is f = 101,700,000 Hz

We need to find the wavelength of WFNX’s radio waves. The relation between wavelength, frequency and speed of a wave is given by :

v=f\lambda

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\lambda=\dfrac{v}{f}\\\\\lambda=\dfrac{3\times 10^8}{101,700,000}\\\\\lambda=2.94\ m

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3 0
3 years ago
Calcular la rapidez promedio
Vlada [557]

Answer:

  v_average = 15 m / s

Explanation:

The average speed can be found in two ways,

* taking the distance traveled and divide it by the time spent

* taking the velocities in each time interval and then finding the weighted average by the time fraction

              v_average = 1 / t_total ∑  v_{i}  t_{i}vi ti

Let's apply this last equation

               

Total time is

               t = t₁ + t₂

               t = 10 + 10 = 20   min

              v_average = 10/20 10 + 10/20 20

              v_average = 10/2 + 20/2

              v_average = 15 m / s

7 0
3 years ago
Antonina throws a coin straight up from a height of
vichka [17]

Answer:

s=vt-\frac{1}{2}gt^2

Explanation:

We could use the following suvat equation:

s=vt-\frac{1}{2}gt^2

where

s is the vertical displacement of the coin

v is its final velocity, when it hits the water

t is the time

g is the acceleration of gravity

Taking upward as positive direction, in this problem we have:

s = -1.2 m

g=-9.8 m/s^2

And the coin reaches the water when

t = 1.3 s

Substituting these data, we can find v:

v=\frac{s}{t}+\frac{1}{2}gt=-\frac{1.2}{1.3}+\frac{1}{2}(-9.8)(1.3)=-7.3 m/s

where the negative sign means the direction is downward.

5 0
3 years ago
Como foi a despedida do bilhete?​
Dmitrij [34]
Can you translate to english ?
8 0
3 years ago
What is the velocity if your going 105 miles every 10 minutes
Afina-wow [57]
The speed is 10.5 miles per minute, or 630 miles per hour.
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8 0
3 years ago
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