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abruzzese [7]
3 years ago
15

A girl pulls a sled with a force of 15 N over a distance of 3 m. What is the kinetic energy of the sled after she pulls it? Assu

me there is no friction.
Physics
2 answers:
docker41 [41]3 years ago
5 0

Answer:

Kinetic energy, KE = 45 J

Explanation:

It is given that,

Force applied by girl on a sled, F = 15 N

It moves a distance, d = 3 m

We need to find the kinetic energy of the sled after she pulls it. We know that the work done is equal to the change in kinetic energy

W=\Delta E=K_f-K_i

K_i=0 (initial at rest)

KE=W=F\times d

KE=15\ N\times 3\ m=45\ J

So, the kinetic energy of the sled after she pulls it is 45 J. Hence, this is the required solution.

Ivenika [448]3 years ago
3 0
The answer is 45 because you multiply 15 x 3 
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A coil of wire containing N turns is in an external magnetic field that is perpendicular to the plane of the coil and it steadil
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Answer:

The Resultant Induced Emf in coil is 4∈.

Explanation:

Given that,

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To find :-

find the induced Emf if rate of change of the magnetic field and the number of turns in the coil are Doubled (but nothing else changes).

So,

   Emf induced in the coil represented by formula

                          ∈  =   -N\frac{d\phi}{dt}                                  ...................(1)

                                          Where:

                                                    .   \phi = BAcos\theta     { B is magnetic field }

                                                                                 {A is cross-sectional area}

                                                    .  N = No. of turns in coil.

                                                    .  \frac{d\phi}{dt} = Rate change of induced Emf.

Here,

Considering the case :-

                                    N1 = 2N  &      \frac{d\phi1}{dt} = 2\frac{d\phi}{dt}

Putting these value in the equation (1) and finding the  new emf induced (∈1)

                           

                                      ∈1 =-N1\times\frac{d\phi1}{dt}

                                      ∈1 =-2N\times2\frac{d\phi}{dt}

                                       ∈1 =4 [-N\times\frac{d\phi}{dt}]

                                        ∈1 = 4∈             ...............{from Equation (1)}      

Hence,

The Resultant Induced Emf in coil is 4∈.        

                           

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