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aliina [53]
3 years ago
11

Please help me! to prove this equation of a thin convex lens..​

Physics
1 answer:
kipiarov [429]3 years ago
5 0

Answer:

can u try to calculate it and you will get the answer

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Puck B has twice the mass of puck A. Starting from rest, both pucks are pulled the same distance across frictionless ice by stri
gogolik [260]

Answer:

(a) 1 : 2

(b) same

Explanation:

Let the mass of puck A is m and the mass of puck B is 2 m.

initial speed for both the pucks is same as u and the distance is same for both is s.

let the tension is T for same.

The kinetic energy is given by

K = 0.5 mv^2

(a) As the speed is same, so the kinetic energy depends on the mass.

So, kinetic energy of A : Kinetic energy of B = m : 2m  = 1 : 2

(b) A the distance s same so the final velocities are also same.

8 0
2 years ago
What is meant by the term 'mass movement'?
vitfil [10]
Mass movement is the movement of surface materials caused by gravity. A great example would be a mud slide.
8 0
3 years ago
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In a certain time interval, natural gas with energy content of 19000 J was piped into a house during a winter day. In the same t
Bumek [7]

Explanation:

Since, it is mentioned the there occurs no change in the temperature. This also means that there will occur no change in thermal energy of the system.

Hence, \Delta E = 0. And, as \Delta E = 0 then there will be no work involved. This means that total energy added to the house will return to the outside air as heat.

Therefore,

                   Q = -(19000 J + 2000 J)

                       = -21000 J

or,    |Q| = 21000 J

Thus, we can conclude that the magnitude of the energy transfer between the house and the outside air is 21000 J.

5 0
3 years ago
A bucket of mass M (when empty) initially at rest and containing a mass of water is being pulled up a well by a rope exerting a
Naily [24]

Answer:

V=\dfrac{PT}{m}\ ln\dfrac{M+m}{M}-gT

Explanation:

Given that

Constant rate of leak =R

Mass at time T ,m=RT

At any time t

The mass = Rt

So the total mass in downward direction=(M+Rt)

Now force equation

(M+Rt) a =P- (M+Rt) g

a=\dfrac{P}{M+Rt}-g

We know that

a=\dfrac{dV}{dt}

\dfrac{dV}{dt}=\dfrac{P}{M+Rt}-g

\int_{0}^{V}V=\int_0^T \left(\dfrac{P}{M+Rt}-g\right)dt

V=\dfrac{P}{R}\ ln\dfrac{M+RT}{M}-gT

V=\dfrac{PT}{m}\ ln\dfrac{M+m}{M}-gT

This is the velocity of bucket at the instance when it become empty.

6 0
3 years ago
You toss a coin into a wishing well full of a liquid denser than the coin. Which of the following could be true?
maks197457 [2]
If one of the answers are the coin will float that one would be correct.
8 0
3 years ago
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