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3 years ago

11

Please help me! to prove this equation of a thin convex lens..

1 answer:

kipiarov [429]3 years ago

5 0

Answer:

can u try to calculate it and you will get the answer

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A ray of light traveling through air strikes a piece of diamond at an angle of incidence equal to 56 degrees. Calculate the angu

Montano1993 [528]

Answer:

The angle of separation is $\Delta \theta = 0.93 ^o$

Explanation:

From the question we are told that

The angle of incidence is $\theta _ i = 56^o$

The refractive index of violet light in diamond is $n_v = 2.46$

The refractive index of red light in diamond is $n_r = 2.41$

The wavelength of violet light is $\lambda _v = 400nm = 400*10^{-9}m$

The wavelength of red light is $\lambda _r = 700nm = 700*10^{-9}m$

Snell's Law can be represented mathematically as

$\frac{sin \theta_i}{sin \theta_r} = n$

Where $\theta_r$ is the angle of refraction

=> $sin \theta_r = \frac{sin \theta_i}{n}$

Now considering violet light

$sin \theta_r__{v}} = \frac{sin \theta_i}{n_v}$

substituting values

$sin \theta_r__{v}} = \frac{sin (56)}{2.46}$

$sin \theta_r__{v}} = 0.337$

$\theta_r__{v}} = sin ^{-1} (0.337)$

$\theta_r__{v}} = 19.69^o$

Now considering red light

$sin \theta_r__{R}} = \frac{sin \theta_i}{n_r}$

substituting values

$sin \theta_r__{R}} = \frac{sin (56)}{2.41}$

$sin \theta_r__{R}} = 0.344$

$\theta_r__{R}} = sin ^{-1} (0.344)$

$\theta_r__{R}} = 20.12^o$

The angle of separation between the red light and the violet light is mathematically evaluated as

$\Delta \theta = \theta_r__{R}} - \theta_r__{V}}$

substituting values

$\Delta \theta =20.12 - 19.69$

$\Delta \theta = 0.93 ^o$

6 0

4 years ago

A harmonic force of maximum value 25 N and frequency of 180 cycles>min acts on a machine of 25 kg mass. Design a support syst

kramer

Answer:

registrar y de h2rhrjlekeek tert2h2jwkwlwlwlwlwlwñlwk

3 0

3 years ago

Please help ASAP please

Alex_Xolod [135]

Answer:

14

Explanation:

6 0

3 years ago

What do we call the potential mechanical energy stored in an object when work is performed to change its shape?

Tom [10]

C) kinetic energy :)

7 0

3 years ago

g The speed of light in a vacuum is larger for short wavelength electromagnetic waves. larger for high frequency electromagnetic

Orlov [11]

Answer:

A constant value everywhere in the universe.

Explanation:

The speed of light in a vacuum is a constant value. It is not affected by change in frequency or wavelength of the light.

Mathematically the speed of light is given as:

c = λf

where λ = wavelength and f - frequency

The speed of light is the constant of proportionality between frequency and wavelength. In order words, wavelength and frequency are inversely proportional. As the wavelength increases, frequency decreases and vice versa.

While the change in wavelength and frequency of light affect the energy of the light, its speed is a constant value as long as the medium is a vacuum.

The speed of light is also not dependent on the manner with which the light wave is moving.

4 0

3 years ago