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lesantik [10]
2 years ago
5

¿Qué establece la ley de la conservación de la materia? Explicar.

Chemistry
1 answer:
masya89 [10]2 years ago
5 0

La materia no se crea ni se destruye solo se transforma

Explanation:

«En toda reacción química la masa se conserva, es decir, la masa total de los reactivos es igual a la masa total de los productos».

Los átomos ni de crean ni se destruyen,durante una reacción química.Por lo tanto una ecuación química ha de tener el mismo numero de atomos de cada elemento a ambos lados de la flecha. Se dice entonces que la ecuación esta balanceada

Espero y te sirva!!

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Because this compound does not have plane of symmetry (POS) and center  of symmetry (COS) i.e. does not have di-symmetry . And also forms non superimposable mirror image . the compound is optically active .

It has  chiral center.

Here , the chiral carbon is attached to the 4 distinct groups such as :  methyl , ethyl , bromine , bromomethane .

<h3>What is di-symmetry?</h3>

Di-symmetry is that which have no center of symmetry and plane of symmetry and alternate axis of symmetry .

<h3>Chiral center :</h3>

Have Sp3 hybridized center (4sigma bond ) .

4 distinct group  is attached to the chiral atom. form non -superimposable mirror image .

<h3>What is optical isomerism ?</h3>

Same molecular formula and same structural formula . also have same physical and chemical properties .

They differ in their behavior towards plane polarized light (ppl) .

Learn more about chiral center here:

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The combustion of propane may be described by the chemical equation C 3 H 8 ( g ) + 5 O 2 ( g ) ⟶ 3 CO 2 ( g ) + 4 H 2 O ( g ) C
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Answer: 72 grams of O_2(g) are needed to completely burn 19.7 g C_3H_8(g)

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According to avogadro's law, 1 mole of every substance weighs equal to molecular mass and contains avogadro's number 6.023\times 10^{23} of particles.

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Putting in the values we get:

\text{Number of moles}=\frac{19.7g}{44g/mol}=0.45moles

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