1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Rzqust [24]
4 years ago
14

Which two substances are among the six most abundant elements in living

Chemistry
1 answer:
denis23 [38]4 years ago
3 0

Answer:

nitrogen

Explanation:

Living organisms often contain trace amounts of several elements, but the most abundant ones are oxygen, carbon, hydrogen, nitrogen, calcium and phosphorus.

Oxygen. ...

Carbon. ...

Hydrogen. ...

Nitrogen. ...

Sulfur. ...

Phosphorus.

You might be interested in
2CuS + 3O2 = 2CuO + 2SO2
Nata [24]
I have no yuuuuu to say anything abt to
4 0
3 years ago
Determine the total pressure of all gases (at STP) formed when 50.0 mL of TNT (C3H5(NO3)3, , molar mass = 227.10 g/mol) reacts a
bija089 [108]

Answer:

Total pressure is 1189 atm

Explanation:

This is the reaction:

4C₃H₅(NO₃)₃  →  6N₂  +  O₂  +  12CO₂  +  10H₂O

As we have the volume of TNT, we must know the density to find out the mass and then, apply molar mass to calculate mole.

TNT density = 1.654 g/mL

Density = mass / volume

1.654 g/mL = TNT mass / 50mL

1.654 g/mL . 50mL = TNT mass → 82.7 g

Mass / Molar mass = Mol → 82.7 g / 227.1 g/m = 0.364 mole

Now, we can calculate all the mole for the formed gases.

4 mole of TNT produce 6 mole N₂ ___ 1 mol O₂ __ 12 mole dioxide __ 10 mole of water

0.364 mole of TNT will produce:

- (0.364  . 6) /4 = 0.546 mole of produced nitrogen

- (0.364 . 1) /4 =  0.091 mole of produced oxygen

- (0.364 . 12) /4 = 1.092 mole of produced dioxide

- (0.364 . 10) /4 = 0.91 mole of produced vapour of water.

Total mole = 0.564 + 0.091 + 1.092 + 0.91 = 2.657 mole

Let's apply the Ideal Gases Law to find the total pressure, at STP

In STP, pressure is 1 atm for 1 mole at 273K, in a volume of 22.4 mL

But we have a volume of 50mL, and we have 2.657 total mole

Don't forget to convert 50 mL to L, cause the units for R

50 mL = 0.050L

P . 0.050L = 2.657 mol . 0.082L.atm/mol.K . 273K

P = (2.657 mol . 0.082L.atm/mol.K . 273K) / 0.050L

P = 1189 atm

3 0
3 years ago
when magnesium is burned in air the mass of the product is greater than the mass of the solid magnesium burned. A student claims
Nikitich [7]
Veg egverbygbe rbbnfghjufddfg
5 0
3 years ago
Read 2 more answers
During which stage of life is a human most dependent on others?
AfilCa [17]

Erm, I think when they are little. When they are just born.

7 0
3 years ago
Read 2 more answers
True or false
svlad2 [7]

Answer:

1. true

2. false

3. true

4. true

Explanation:

I believe these are the answers, I'm just not sure for #3

4 0
3 years ago
Other questions:
  • Hurry please!! Needs to be turned in by 20 minutes!! Describe the two main factors the influence the path of surface currents. W
    9·1 answer
  • Match the organelles to their functions. Tiles Golgi apparatus lysosome smooth endoplasmic reticulum nucleus Pairs produces lipi
    14·2 answers
  • Consider the reaction of phosphorus with water and iodine. 2P (s) 6H2O (l) 3I2 (s) 6HI (aq) 2H3PO3 (aq) Determine the limiting r
    14·1 answer
  • the density of iron is 7.86 g/cm3. you are given an unknown metal that has a mass of 214.6 g. what would the volume of the sampl
    6·2 answers
  • What would be the IUPAC name of PoTs2
    15·1 answer
  • How would decreasing the pressure affect the equilibrium of this reaction? Hat 12 32H1 O A. The reaction would remain in equilib
    8·2 answers
  • PLEASE HELP IT'S URGENT
    14·2 answers
  • If the shape of the moon appears to be increasing over time, what is
    9·2 answers
  • What element was oxidized and reduced in this reaction and what is the oxidizing and the reducing agent for this reaction? Au(NO
    6·1 answer
  • Ca(s) + O₂(g) + S(s) → CaSO4(s)
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!