Should I use flex seal to clean a baby

Concentrated HCl is 15 M (15 molar). A 500 mL quantity of this solution is diluted by adding water to give a final volume of 2.5

Murrr4er [49]

The molarity of the resulting solution obtained by diluting the stock solution is 3 M

<h3>Data obtained from the question </h3>

Molarity of stock solution (M₁) = 15 M
Volume of stock solution (V₁) = 500 mL
Volume of diluted solution (V₂) = 2.5 L = 2.5 × 1000 = 2500 mL
Molarity of diluted solution (M₂) =?

<h3>How to determine the molarity of diluted solution </h3>

M₁V₁ = M₂V₂

15 × 500 = M₂ × 2500

7500 = M₂ × 2500

Divide both side by 2500

M₂ = 7500 / 2500

M₂ = 3 M

Thus, the volume of the resulting solution is 3 M

Learn more about dilution:

brainly.com/question/15022582

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7 0

1 year ago

We make a basic solution by mixing 50. mL of 0.10 M NaOH and 50. mL of 0.10 M Ca(OH)2. It requires 250 mL of an HCl solution to

andreyandreev [35.5K]

<u>Answer:</u> The correct answer is Option 5.

<u>Explanation:</u>

To calculate the molarity of the solution after mixing 2 solutions, we use the equation:

$M=\frac{n_1M_1V_1+n_2M_2V_2}{V_1+V_2}$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of the NaOH.

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of the $Ca(OH)_2$

We are given:

$n_1=1\\M_1=0.10M\\V_1=50mL\\n_2=2\\M_2=0.1\\V_2=50mL$

Putting all the values in above equation, we get:

$M=\frac{(1\times 0.1\times 50)+(2\times 0.1\times 50)}{50+50}\\\\M=0.15M$

To calculate the molarity of acid, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is $HCl$

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base.

We are given:

$n_1=1\\M_1=?M\\V_1=250mL\\n_2=1\\M_2=0.15M\\V_2=100mL$

Putting values in above equation, we get:

$1\times M_1\times 250=1\times 0.15\times 100\\\\M_1=0.06M$

Hence, the correct answer is Option 5.

7 0

3 years ago

What is one of the main features of karst topography?

Sauron [17]

Answer:

Karst is a topography formed from the dissolution of soluble rocks such as limestone, dolomite, and gypsum. It is characterized by underground drainage systems with sinkholes and caves. It has also been documented for more weathering-resistant rocks, such as quartzite, given the right conditions.

4 0

2 years ago

Read 2 more answers

Why do gases diffuse faster than liquids? Gas particles have more kinetic energy a liquid does not have as many particles liquid

Readme [11.4K]

Gases have more kinetic energy

5 0

3 years ago

Read 2 more answers

Here is the information: A 1.2516 gram sample of a mixture of CaCO3 and Na2SO4 was analyzed by dissolving the sample and adding

tiny-mole [99]

Answer:

93,32 % (w/w)

Explanation:

The Ca²⁺ of CaCO₃ was completely precipitate to CaC₂O₄ that results in H₂C₂O₄. The titration of this one is:

3H₂C₂O₄ + 2H⁺ + MnO₄⁻ → Mn²⁺ + 4H₂O + 6CO₂

As you required 35,62mL of 0,1092M MnO₄⁻, the moles of H₂C₂O₄ are:

0,03562L× $\frac{0,1092M}{L}$ =

3,890x10⁻³mol of MnO₄⁻× $\frac{3molH_{2}C_{2}O_{4}}{1mol MnO_{4}^-}$ = <em>0,01167 mol of H₂C₂O₄</em>

The number of moles of CaCO₃ are the same number of moles of H₂C₂O₄ because every Ca²⁺ was converted in CaC₂O₄ that was converted in H₂C₂O₄. That means: <em>0,01167 mol of CaCO₃</em>

0,01167 mol of CaCO₃ are:

0,01167 mol of CaCO₃× $\frac{100,0869g}{1mol}$ = <em>1,168 g of CaCO₃</em>

As the mass of the initial mixture is 1,2516 g, the percentage by weight of CaCO₃ is:

$\frac{1,168g}{1,2516g}$ ×100 = <em>93,32 % (w/w)</em>

I hope it helps!

7 0

3 years ago