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JulijaS [17]
3 years ago
15

Bromine (Br,) is observed as a red-brown color During the bromination of benzene, an electrophilic aromatic substitution, why do

es the red-brown color of Br2 disappear as the reaction progresses?
a. The bromine (Br2) dissolves in the solution and becomes colorless
b. The bromine (Br2) has reacted with the benzene, leaving fewer bromine molecules in solution.
c. The bromine (Br,) reacts with acid to produce HBr, which is colorless .
d. The bromine (Br,) leaves the mixture as bromine gas .
Chemistry
1 answer:
sergey [27]3 years ago
4 0

Answer:

b. The bromine (Br2) has reacted with the benzene, leaving fewer bromine molecules in solution.

Explanation:

Colour is caused by absorption of light of the frequency of “complementary colours”. Exactly which frequencies molecules absorb depends on the arrangement of electrons. Obviously, to break the Br-Br bond and the C=C bond in the reactants and replace them with two C-H bonds is a significant reordering of electrons and so the new molecule is no longer able to absorb the same frequencies as previously. Hence, a colour change, in this case from orange to colourless.

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A 1.10 g sample contains only glucose and sucrose. When the sample is dissolved in water to a total solution volume of 25.0L, th
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Answer:

\large \boxed{79 \, \%}

Explanation:

I assume the volume is 2.50 L. A volume of 25.0 L gives an impossible answer.

We have two conditions:

(1) Mass of glucose + mass of sucrose = 1.10 g

(2) Osmotic pressure of glucose + osmotic pressure of sucrose = 3.78 atm

Let g = mass of glucose

and s = mass of sucrose. Then  

g/180.16 = moles of glucose, and

s/342.30 = moles of sucrose. Also,

g/(180.16×2.50) = g/450.4 = molar concentration of glucose. and

s/(342.30×2.50) = s/855.8 = molar concentration of sucrose.

1. Set up the osmotic pressure condition

Π = cRT, so

\begin{array}{rcl}\Pi_{\text{g}} +\Pi_{\text{s}}&=&\Pi_{\text{tot}}\\\dfrac{g}{450.4}\times8.314\times298 + \dfrac{s}{855.8}\times8.314\times298 & = & 3.78\\\\5.501g + 2.895s & = & 3.78\\\end{array}

Now we can write the two simultaneous equations and solve for the masses.

2. Calculate the masses

\begin{array}{lrcl}(1)& g + m & = & 1.10\\(2) &5.501g +2.895s & = & 3.78\\(3) & m & = &1.10 - g\\&5.501g + 2.895(1.10 - g) & = & 3.78\\&2.606g + 3.185 & = & 3.78\\ &2.606g & = & 0.595\\(4)  & g & = & \mathbf{0.229}\\&0.229 + s & = & 1.10\\& s & = & \mathbf{0.871}\\\end{array}

We have 0.229 g of glucose and 0.871 g of sucrose.

3. Calculate the mass percent of sucrose

\text{Mass percent} = \dfrac{\text{Mass of component}}{\text{Total mass}} \times \, 100\%\\\\\text{Percent sucrose} = \dfrac{\text{0.871 g}}{\text{1.10 g}} \times \, 100\% = 79 \, \%\\\\\text{The mixture is $\large \boxed{\mathbf{79 \, \%}}$ sucrose}

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3 years ago
How can i find nuclear charge and overall charge while only knowing the atomic mumber, number of protons and electrons?​
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Explanation:

An atom is made up of:

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Atomic number is the number of protons in an atom.

To find the nuclear charge:

    We use the effective nuclear charge formula:

   Effective nuclear charge = Atomic number - number of shielding electrons(non-valence electrons)

The shielding electrons are the non-valence electrons in the inner orbitals.

For example:

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          Effective nuclear charge = 10 - (2) = 8+

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The effective nuclear charge is 8+

Overall charge:

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  For neutral atoms, the overall charge is zero as the number of protons and electrons are the same.

 

Learn more:

Effective nuclear charge brainly.com/question/5441986

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the answer is ClF3 on edge

Explanation:

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Answer:

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Explanation:

<u>5800n x 20m</u>        =1450w

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