Electronic configuration: The distribution or arrangement of electrons of a molecule or an atom in molecular or atomic orbitals.
Ground state electron configuration: The distribution of electrons of an atom or molecule around the nucleus with lower levels of energy.
Now,
stands for Ruthenium with atomic number 44. It is a metal and thus, has ability to lose electrons and, becomes positively charged ion.
One can write the electronic configuration with the help of atomic number and Afbau principle, Pauli exclusion principle etc.
Ground electronic Configuration is as follows:

Soft Hand notation: ![[Kr]4d^{7}5s^{1}](https://tex.z-dn.net/?f=%5BKr%5D4d%5E%7B7%7D5s%5E%7B1%7D)
Now, when ruthenium loses two electrons then it becomes
, thus electron configuration becomes
Soft Hand notation: ![[Kr]4d^{6}](https://tex.z-dn.net/?f=%5BKr%5D4d%5E%7B6%7D)
The ground state electronic configuration of Ruthenium is
and when it loses two electrons, then electronic configuration becomes
(
)
As long as the chemical is not used up in the reaction the answer is true
10 electrons
Explanation:
The maximum number of electrons in a single d-subshell is 10 electrons.
The d-notation stands for an azimuthal quantum number or secondary quantum number.
This subshell can only accommodate a maximum of 10 electrons.
d- subshell has five orbitals
Each orbital is able to accommodate 2 electrons.
Therefore 5 x 2 = 10 electrons
learn more:
Atomic orbital brainly.com/question/1832385
#learnwithBrainly
The concentration of [H3O⁺]=2.86 x 10⁻⁶ M
<h3>Further explanation</h3>
In general, the weak acid ionization reaction
HA (aq) ---> H⁺ (aq) + A⁻ (aq)
Ka's value
![\large {\boxed {\bold {Ka \: = \: \frac {[H ^ +] [A ^ -]} {[HA]}}}}](https://tex.z-dn.net/?f=%5Clarge%20%7B%5Cboxed%20%7B%5Cbold%20%7BKa%20%5C%3A%20%3D%20%5C%3A%20%5Cfrac%20%7B%5BH%20%5E%20%2B%5D%20%5BA%20%5E%20-%5D%7D%20%7B%5BHA%5D%7D%7D%7D%7D)
Reaction
HC₂H₃O₂ (aq) + H₂O (l) ⇔ (aq) + H₃O⁺ (aq) Ka = 1.8 x 10⁻⁵
![\tt Ka=\dfrac{[C_2H_3O^{2-}[H_3O^+]]}{[HC_2H_3O_2]}}\\\\1.8\times 10^{-5}=\dfrac{0.22\times [H_3O^+]}{0.035}](https://tex.z-dn.net/?f=%5Ctt%20Ka%3D%5Cdfrac%7B%5BC_2H_3O%5E%7B2-%7D%5BH_3O%5E%2B%5D%5D%7D%7B%5BHC_2H_3O_2%5D%7D%7D%5C%5C%5C%5C1.8%5Ctimes%2010%5E%7B-5%7D%3D%5Cdfrac%7B0.22%5Ctimes%20%5BH_3O%5E%2B%5D%7D%7B0.035%7D)
[H₃O⁺]=2.86 x 10⁻⁶ M
B
When frequency increases, as does the energy, but wavelength decreases. It also works vise versa; if wavelength were to increase, its frequency and energy will decrease.