Answer:
A.) 8 m/s
B.) 7.0 m
Explanation:
Given that a block is given an initial velocity of 8.0 m/s up a frictionless 28° inclined plane. 
(a) What is its velocity when it reaches the top of the plane? 
Since the plane is frictionless, the final velocity V will be the same as 8 m/s
The velocity will be 8 m/s as it reaches the top of the plane.
(b) How far horizontally does it land after it leaves the plane?
For frictionless plane, 
a = gsinø
Acceleration a = 9.8sin28
Acceleration a = 4.6 m/s^2
Using the third equation of motion 
V^2 = U^2 - 2as 
Substitute the a and the U into the equation. Where V = 0
0 = 8^2 - 2 × 4.6 × S
9.2S = 64
S = 64/9.2
S = 6.956 m
S = 7.0 m
 
        
             
        
        
        
Answer:
both experience forces or at least a force
Explanation:
it would go in the direction the other object
 (second object, the one that crashed) was going
 si if going right then right if left then left 
plus or minus
 
        
             
        
        
        
Answer:
D
Explanation:
the answer is d your welcome