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pochemuha
3 years ago
7

How many grams of oxygen are required to produce

Chemistry
1 answer:
Likurg_2 [28]3 years ago
8 0

Answer:

8 GRAMS OF OXYGEN WILL BE REQUIRED TO PRODUCE 9 GRAMS OF WATER MOLECULES.

Explanation:

The equation for the reaction is;

2 H + O2 ----> 2 H2O          

(H = 1, O = 16)

From the reaction, it can be observed that 1 mole of O2 reacts to form 2 moles of H2O

At STP, using the molar masses of the elememts and compound in the reaction, 32 g of O2 will reacts to form 36 g (18 * 2 g) of H2O

32 g of O2 = 36 g OF H2O

if 9 grams of H2O is produced, the mass of oxygen required to produce it will be:

( 32 * 9 / 36 ) g of O2

= (288 / 36) g

= 8 g of O2

So, 8 grams of Oxygen will be required to produce 9 grams of water.

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Calcuate the number of<br> grams of solute in 453.9mL<br> of 0.237 M calcium acetate
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The number of  grams : 17.082 g

<h3>Further explanation</h3>

Molarity shows the number of moles of solute in every 1 liter of solute or mmol in each ml of solution

\large {\boxed {\bold {M ~ = ~ \dfrac {n} {V}}}

Where

M = Molarity

n = Number of moles of solute

V = Volume of solution

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  • mol

\tt mol=M\times V=0.237\times 0.4539=0.108

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MW Ca(C₂H₃OO)₂ : 158,17 g/mol

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