Match the name of each gas law to the properties it compares. 1. Gay-Lussac's law 2. Boyle's law 3. Avogadro's law a. Volume and
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Answer: Reducing agent in the given reaction is .
Explanation:
A reducing agent is defined as an element which tends to lose electrons to other element leading to an increase in its oxidation number.
In the given reaction, oxidation state of sulfur in is +2 and
has 0 oxidation state.
In oxidation state of S is 2.5 and in
oxidation state of I is -1.
Since, an increase in oxidation state of S is occurring from +2 to +2.5. Hence, it is acting as a reducing agent.
Thus, we can conclude that reducing agent in the given reaction is .
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Answer:
Explanation:
Hello,
In this case, for the equilibrium condition, the equilibrium constant is defined via the law of mass action, which states that the division between the concentrations of the products over the concentration of the reactants at equilibrium equals the equilibrium constant, for the given reaction:
The suitable equilibrium constant turns out:
Or in terms of the initial equilibrium constant:
Since the second reaction is a doubled version of the first one.
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