What is the oxidation number for S in the compound SO3? (Recall that O has an oxidation number of –2.) A. 0

Chemistry

2 answers:

Snezhnost [94]3 years ago

4 0

Answer:

$\boxed {\boxed {\sf +6}}$

Explanation:

A compound must have a net charge of 0. The charges have to balance each other out and equal 0.

We have the compound sulfur trioxide with a chemical formula of SO₃.

Oxygen (O) has an oxidation state of -2, which means it will have a charge of -2 in the compound. However, note there is a subscript after the O in the chemical formula. Therefore, there are 3 oxygen atoms in the compound and each one has a charge of -2. The oxygen has an overall charge of -6 because 3*-2 = -6.

There is only one atom of sulfur (there is no subscript, so a 1 is implied). It has to balance out the -6 charge of the oxygen atoms, so it must be +6.

The oxidation number for sulfur is +6 in the compound sulfur trioxide.

mrs_skeptik [129]3 years ago

4 0

Answer:

Explanation:

edge 2021!

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victus00 [196]

Answer:

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Explanation:

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3 years ago

A student wants to reclaim the iron from an 18.0-gram sample of iron(III) oxide, which

lilavasa [31]

Answer:

$m_{Fe}=12.6gFe$

Explanation:

Hello,

In this case, since we have grams of iron (III) oxide whose molar mass is 159.69 g/mol are able to compute the produced grams of iron by using its atomic mass that is 55.845 g/mol and their 2:4 molar ratio in the chemical reaction:

$m_{Fe}=18.0gFe_2O_3*\frac{1molFe_2O_3}{159.69gFe_2O_3}*\frac{4molFe_2O_3}{2molFe_2O_3} *\frac{55.845gFe}{1molFe_2O_3} \\\\m_{Fe}=12.6gFe$