Question

What is the oxidation number for S in the compound SO3? (Recall that O has an oxidation number of –2.) A. 0

Answer 1

Answer:

$\boxed {\boxed {\sf +6}}$

Explanation:

A compound must have a net charge of 0. The charges have to balance each other out and equal 0.

We have the compound sulfur trioxide with a chemical formula of SO₃.

Oxygen (O) has an oxidation state of -2, which means it will have a charge of -2 in the compound. However, note there is a subscript after the O in the chemical formula. Therefore, there are 3 oxygen atoms in the compound and each one has a charge of -2. The oxygen has an overall charge of -6 because 3*-2 = -6.

There is only one atom of sulfur (there is no subscript, so a 1 is implied). It has to balance out the -6 charge of the oxygen atoms, so it must be +6.

The oxidation number for sulfur is +6 in the compound sulfur trioxide.

Answer 2

Answer:

+6

Explanation:

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