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Lerok [7]
3 years ago
9

Select the expression that equals 9-(-15) a.9+(15) b. -9+15 c. 9+(-15) d. -9+-15

Mathematics
1 answer:
madreJ [45]3 years ago
4 0

Answer:

Step-by-step explanation: PURPLE

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Plz help me im trying to defeat a boss
Wittaler [7]

Answer:

15200

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
A rug shaped like a rectangle is 2.5 meters long and 1.8 meters wide what is the perimeter in meters of the rug
Novosadov [1.4K]

Answer:

P = 8.6 m

Step-by-step explanation:

Given that,

The length of a rectangle = 2.5 m

The width of a rectangle = 1.8 m

We need to find the perimeter of the rug. The perimeter of a rectangle is given by :

P=2(l+b)

= 2(2.5+1.8)

= 8.6 m

So, the perimeter of the rug is 8.6 m.

6 0
3 years ago
If(x)= 2e^x-1 +3 , what is f^-1 (x)
Rainbow [258]

Answer:

f^-1 (x) =  1+ln( (x-3)/2)

Step-by-step explanation:

hello :

let f(x) = y  so : y = 2e^(x-1) +3

calculate x :  e^(x-1) = (y-3)/2

for : y-3 > 0 :  x-1 = ln( (y-3)/2)    so : x= 1+ln( (y-3)/2)

If(x)= 2e^(x-1) +3 , what is f^-1 (x) =  1+ln( (x-3)/2)

4 0
3 years ago
If the length of diagonal of a square is 4√2 cm, find it's length, perimeter and area.​
Sonbull [250]

Answer:

As Per Provided Information

  • Length of diagonal of square is 4√2 cm

We have been asked to find the length , perimeter and area of square .

First let's calculate the side of square .

Using Formulae

\boxed{\bf \:Diagonal_{(Square)} \:  = side \sqrt{2}}

On substituting the value in above formula we obtain

\qquad\longrightarrow\sf  \:4 \sqrt{2}  = side \sqrt{2}  \\  \\  \\ \qquad\longrightarrow\sf  \:4  \cancel{\sqrt{2}} = side \cancel{ \sqrt{2}} \\  \\  \\  \qquad\longrightarrow\sf  \:side \:  = 4 \: cm

<u>Therefore</u><u>,</u>

  • <u>Length </u><u>of </u><u>its </u><u>side </u><u>is </u><u>4</u><u> </u><u>cm</u><u>.</u>

Finding the perimeter of square.

\boxed{\bf \: Perimeter_{(Square)} = 4 \times side}

Substituting the value we obtain

\qquad\longrightarrow\sf  \:Perimeter_{(Square)} \:  = 4 \times 4 \\  \\  \\ \qquad\longrightarrow\sf  \:Perimeter_{(Square)} = 16 \: cm

<u>Therefore</u><u>,</u>

  • <u>Perimeter </u><u>of </u><u>square </u><u>is </u><u>1</u><u>6</u><u> </u><u>cm </u><u>.</u>

Finding the area of square .

\boxed{\bf \: Area_{(Square)} =  {side}^{2}}

Substituting the value we get

\qquad\longrightarrow\sf  \:Area_{(Square)} \:  =  {4}^{2}  \\  \\  \\ \qquad\longrightarrow\sf  \:Area_{(Square)} = 16 \:  {cm}^{2}

<u>Therefore</u><u>,</u>

  • <u>Area </u><u>of</u><u> </u><u>square</u><u> </u><u>is </u><u>1</u><u>6</u><u> </u><u>cm²</u><u>.</u>
3 0
2 years ago
Make sure your answer is in
romanna [79]

Answer:

210° , 330°

Step-by-step explanation:

using the sides of the 30- 60- 90 triangle

with legs 1, \sqrt{3} and hypotenuse 2 , then

sin^{-1} \frac{1}{2} = 30° ← related acute angle

since sin^{-1} - \frac{1}{2}

then angle is in third / fourth quadrants , then required angles are

180° + 30° = 210° ← in third quadrant

360° - 30° = 330° ← in fourth quadrant

6 0
2 years ago
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