MgSO4, CO2, AlCl3 are the answer
The grams of CuCl2 required to prepare 1250g of 1.25% by mass is calculated as follow
1250 = 100%
what about 1.25%
by cross multiplication
= 1.25 x1250/100 = 15.63 grams
Atomic mass gold ( Au) = 196.96 a.m.u
196.96 g ------------ 6.02x10²³ atoms
2.35 g -------------- ??
2.35 x (6.02x10²³) / 196.96
=> 7.18x10²¹ atoms
The anticodons corresponding to the codons on the mRNA (from part A) is 5' CGA - AAA - GUU 3'.
<h3>What are anticodons?</h3>
Anticodons are nucleotide sequences on tRNA molecules that are complementary to the codons found on mRNA molecules.
The anticodons on tRNA molecules determine the amino acid that is carried by the tRNA.
Just like codons, anticodons occur in triplets of nucleotide sequences.
Considering the codons on the mRNA molecule:
3’ GCT | TTT | CAA | AAA ’5
The complementary anticodon will be:
5' CGA - AAA - GUU 3'
Learn more about anticodons at:brainly.com/question/28067314
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