All categories

3 years ago

Formula for sodium iodine

Chemistry

2 answers:

ivolga24 [154]3 years ago

7 0

Answer:

NaI

Explanation:

The formula for sodium iodide is NaI

It is a compound (ionic compound) formed by the chemical reaction between sodium, Na and iodine.

The sodium is a metal in group 1 with atomic number 11 and mass number 23 ,it has one valence electron which it gives out to form a cation of +1 charge and the iodine is in group 7(halogen family) with atomic number 57 and mass number 23 and it has 7 valence electrons which allows it attract 1 electron to form an anion(iodide) of charge -1.

The reaction of sodium ion with iodide ion form the sodium iodide where sodium releases its one valence electron and iodine receives it which makes it balance that is they react in ratio 1:1 and thus have a chemical formula of NaI.

NaI has atomic mass of 150g/mole that is 127 + 23 = 150

Where

Na=23g/mol, I = 127g/mol

NaI is used mainly as nutritional supplement

I hope this was helpful, Please mark as brainliest.

Vlad1618 [11]3 years ago

6 0

Nal is the formula for sodium iodine

You might be interested in

A graduated cylinder was filled with 25.0 mL of water. A solid object was immersed in the cylinder, raising the water level to 3

yawa3891 [41]

Answer:

Density of the object is 8759.494 grams/L

Explanation:

As we know density of an object is mass of the object divided by its volume

Given

Volume of the object is equal to the change in volume of water with in the cylinder when the object was immersed in water.

Hence, volume of object is equal to

$32.9 -25 = 7.9$ mL

Mass of the object is $69.2$ grams

Density

$= \frac{69.2}{7.9 *10^{-3}}\\= 8759.494$ grams/L

Density of the object is 8759.494 grams/L

7 0

3 years ago

If the volume of the original sample in Part A ( P1 = 242 torr , V1 = 27.0 L ) changes to 80.0 L , without a change in the tempe

Brrunno [24]

The new pressure is 81.675 torr

Since temperature and moles are held constant, we use Boyle's Law:

A gas law known as Boyle's law asserts that a gas's pressure is inversely proportional to its volume when it is held at a fixed temperature and of a given mass.

To put it another way, as long as the temperature and volume of the gas remain constant, the pressure and volume of the gas are inversely proportional to one another.

The Anglo-Irish chemist Robert Boyle proposed Boyle's law in the year 1662.

P1V1=P2V2. Simply plug in your values. The units can remain in torr. Converting to atmospheres is not needed.

(242 torr)(27.0 L)=P2(80.0 L)

P2=[(242)(27)]/80 = 81.675 torr

Hence The new pressure is 81.675 torr

Learn more about Boyle's Law here

brainly.com/question/26040104

#SPJ4

3 0

2 years ago

When solutions of silver nitrate and sodium chloride are mixed, a precipitation reaction occurs. What mass of precipitate can be

Bas_tet [7]

Explanation:

The given precipitation reaction will be as follows.

$AgNO_{3}(aq) + NaCl(aq) \rightarrow AgCl(s) + NaNO_{3}(aq)$

Here, AgCl is the precipitate which is formed.

It is known that molarity is the number of moles present in a liter of solution.

Mathematically, Molarity = $\frac{\text{no. of moles}}{\text{volume in liter}}$

It is given that volume is 1.14 L and molarity is 0.269 M. Therefore, calculate number of moles as follows.

Molarity = $\frac{\text{no. of moles}}{\text{volume in liter}}$

0.269 M = $\frac{\text{no. of moles}}{1.14 L}$

no. of moles = 0.306 mol

As molar mass of AgCl is 143.32 g/mol. Also, relation between number of moles and mass is as follows.

No. of moles = $\frac{mass}{\text{molar mass}}$

0.307 mol = $\frac{mass}{143.32 g/mol}$

mass = 43.99 g

Thus, we can conclude that mass of precipitate produced is 43.99 g.

8 0

3 years ago

_H2SO4 + __ B(OH)3 = _ B2(SO4)3 + __ H2O

Nana76 [90]

Answer:

3H2SO4 + 2B(OH)3 -> B2(SO4)3 + 6H2O

Explanation:

3 0

3 years ago

In one experiment, the reaction of 1.00 mercury and an excess of sulfur yielded 1.16g of a sulfide of mercury

Nuetrik [128]

<u>Answer and Explanation:</u>

Mercury combines with sulfur as follows -

Hg + S = HgS

Hg = 200,59

S = 32,066 Therefore 1.58 g of Hg will react with -

1.58 multiply with 32,066 divide by 200,96 of sulfur.

= 0.25211 g S

This will form 1.58 + 0.25211 g HgS = 1.83211 g HgS

The amount of S remaining = 1.10 - 0.25211 = 0.84789 g

5 0

3 years ago

Formula for sodium iodine​

Formula for sodium iodine