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aivan3 [116]
2 years ago
15

Is it possible to prepare chlorine in lab without application of heat?​

Chemistry
1 answer:
marissa [1.9K]2 years ago
5 0

Answer:

i think it will explode

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What is the concentration of 10.00 mL of HBr if it takes 16.73 mL of a 0.253 M LiOH solution to neutralize it?
Leni [432]
First. let's write the reaction formula: HBr +LiOH ----> LiBr + H₂O

let's get the moles of LiOH first

moles= Molarity x Liters

moles= 0.253 M x 0.01673 Liter= 0.00423 moles LiOH

using the balanced equation, you can see that 1 mol LiOH is equal to 1 mol HBr. so:

0.00423 mol LiOH = 0.00423 mol HBr

now let's find the concentration

molarity= mol/ Liters

0.00423 mol/ 0.01000 Liters= 0.423 M
3 0
3 years ago
Molecules have ionization energies, just like atoms do. The ionization energy for molecular oxygen, for example, is 1314 kJ/mol.
taurus [48]

Answer:

91.1835 nm

Explanation:

Given that the ionization energy of the oxygen molecule = 1314 kJ/mol

It means that

1 mole of oxygen molecules can be ionized by the energy = 1314 kJ = 1314000 J

1 mole of molecules contains 6.022 × 10²³ atoms

So,

6.022 × 10²³ atoms of oxygen molecules can be ionized by the energy = 1314000 J

1 atom require \frac{1314000}{6.022\times 10^{23}}\ J of energy

Energy = 2.18\times 10^{-18}\ J

Also

E=\frac {h\times c}{\lambda}

Where,  

h is Plank's constant having value 6.626\times 10^{-34}\ Js

c is the speed of light having value 3\times 10^8\ m/s

\lambda is the wavelength

So,

\lambda=\frac {h\times c}{E}

\lambda=\frac{6.626\times 10^{-34}\times 3\times 10^8}{2.18\times 10^{-18}}\ m

\lambda=91.1835\times 10^{-9}}\ m

Also,

1\ nm=10^{-9}}\ m

So, wavelength = 91.1835 nm

6 0
3 years ago
What is the formula for triboron silicide?
artcher [175]

Answer:

B₃Si

Explanation:

Let's take  break it down. From triboron silicide;

Tri - Three

Triboron - Three boron atoms

Silicide - Silicon (with an -ide suffix)

The formular is given as;

B₃Si

7 0
2 years ago
1. If 22.5 L of nitrogen at 734 mm Hg are compressed to 702 mm Hg at constant
Alika [10]

Answer:

The answer to your question is   V2 = 23.52 l

Explanation:

Data

Volume 1 = V1 = 22.5 l

Pressure 1 = P1 = 734 mmHg

Volume 2 = V2 = ?

Pressure 2 = 702 mmHg

Process

To solve this problem use Boyle's law.

                      P1V1 = P2V2

-Solve for V2

                          V2 = P1V1 / P2

-Substitution

                          V2 = (734 x 22.5) / 702

-Simplification

                           V2 = 16515 / 702

-Result

                           V2 = 23.52 l

-Conclusion

If we diminish the pressure, the volume will be higher.

8 0
3 years ago
Explain how original mass of dry ice compares with the mass of carbon dioxide gas?
MAVERICK [17]
The freezing temperature at a normal sea level air pressure is negative 78.5 degrees.
8 0
3 years ago
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