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aivan3 [116]
3 years ago
15

Is it possible to prepare chlorine in lab without application of heat?​

Chemistry
1 answer:
marissa [1.9K]3 years ago
5 0

Answer:

i think it will explode

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Calculate the ph of a solution whose(oh^-) is 4.583*10^-5 mole dm cube (pkw=14)​
Sergeu [11.5K]

pH of solution = 9.661

<h3>Further explanation </h3>

pH is the degree of acidity of a solution that depends on the concentration of H⁺ ions. The greater the value the more acidic the solution and the smaller the pH.

pH = - log [H⁺]

So that the two quantities between pH and [H⁺] are inversely proportional because they are associated with negative values.

pOH=-log[OH⁻]

\tt pOH=-log[4.583\times 10^{-5}]\\\\pOH=5-log~4.583=4.339

pH+pOH=pKw

\tt pH=14-4.339\\\\pH=9.661

8 0
3 years ago
What happens to a gas as it is cooled below 0*C
Damm [24]

Sorry but it depends on the gas in question and it's temperature of condensing /boiling point if this it 0° it will turn liquid

7 0
4 years ago
Read 2 more answers
vanadium has an atomic mass of 50.9415 amu. it has two common isotopes.one isotopes has a mass of 50.9440 amu and a relative abu
Kaylis [27]

Explanation:

Average atomic mass of the  vanadium = 50.9415 amu

Isotope (I) of vanadium' s abundance = 99.75 %= 0.9975

Atomic mass of Isotope (I) of vanadium ,m= 50.9440 amu

Isotope (II) of vanadium' s abundance =(100%- 99.75 %) = 0.25 % = 0.0025

Atomic mass of Isotope (II) of vanadium ,m' = ?

Average atomic mass of vanadium =

m × abundance of isotope(I) + m' × abundance of isotope (II)

50.9415 amu =50.9440 amu× 0.9975 + m' × 0.0025

m'= 49.944 amu

The atomic mass of isotope (II) of vanadium is 49.944 amu.

5 0
3 years ago
What would be the volume of 12 moles of a gas at STP
Doss [256]
Using PV=nRT
you get 268.976268L
=270L
5 0
3 years ago
A student has a solution of sodium nitrate and believes it is saturated. Which statement provides the best evidence that the sol
zheka24 [161]

It is easiest to tell if a solution is saturated if there is residue on the bottom. If it crystallized, the solution is saturated. If it is a supersaturated solution, there will not be crystallization unless more of the solute is added, at which point all of it will crystallize.

6 0
3 years ago
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