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Galina-37 [17]
3 years ago
6

1. What temperature is equivalent to 32°F?

Chemistry
2 answers:
Vlad1618 [11]3 years ago
4 0

Answer:

0 Celsius

Explanation:

its 0 degrees C

love history [14]3 years ago
3 0

Answer:

0°C =  32°F

Explanation:

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Name the following compound: <br> HC2H3O2
just olya [345]

Answer:

El ácido acético , denominado sistemáticamente ácido etanoico, es un compuesto orgánico líquido incoloro con la fórmula química CH3COOH (también escrito como CH3CO2H o C2H4O2

Explanation:

Cuando no se diluye, a veces se le llama ácido acético glacial . El vinagre es aproximadamente del 3 al 9% de ácido acético en volumen, lo que hace que el ácido acético sea el componente principal del vinagre, aparte del agua.

3 0
3 years ago
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Predict the products of the reaction below
Mrrafil [7]

Answer:

HNO₃ + NaOH ---> NaNO₃ + H₂O

Explanation:

This reaction appears to be a double-displacement reaction. In these reaction, the cation of one compound is swapped with the cation of another.

As such, the hydrogen cation (H⁺) from HNO₃ is swapped with the sodium cation (Na⁺) of NaOH.

Luckily, all of the cations have a +1 charge and the anions have a -1 charge. This means that no coefficients are necessary to balance the reaction.

The <u>complete balanced </u>equation is:

HNO₃ + NaOH ---> NaNO₃ + H₂O

4 0
2 years ago
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The answer would be D carbon dioxide
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3 years ago
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Ultimately the carbon molecules in pyruvate end up as what molecules
jeyben [28]
CO2 Thats your answer
3 0
3 years ago
A concentrated aqueous solution of Pb(NO3)2 is slowly added to 1.0 L of a mixed aqueous solution containing 0.010 M Na2CrO4 and
Oduvanchick [21]

Answer:

This means the amount of PbCrO4 will precipitate first, with a [Pb^2+] concentration of 1.8*10^-12 M

Explanation:

Step 1: Data given

Molarity of Na2CrO4 = 0.010 M

Molarity of NaBr = 2.5 M

Ksp(PbCrO4) = 1.8 * 10^–14

Ksp(PbBr2) = 6.3 * 10^–6

Step 2: The balanced equation

PbCrO4 →Pb^2+ + CrO4^2-

PbBr2  → Pb^2+ + 2Br-

Step 3: Define Ksp

Ksp PbCrO4 = [Pb^2+]*[CrO4^2-]

1.8*10^-14 = [Pb^2+] * 0.010 M

[Pb^2+] = 1.8*10^-14 /0.010

[Pb^2+] = 1.8*10^-12 M

The minimum [Pb^2+] needed to precipitate PbCrO4 is 1.8*10^-12 M

Ksp PbBr2 = [Pb^2+][Br-]²

6.3 * 10^–6 = [Pb^2+] (2.5)²

[Pb^2+] = 1*10^-6 M

The minimum [Pb^2+] needed to precipitate PbBr2 is 1*10^-6 M

This means the amount of PbCrO4 will precipitate first, with a [Pb^2+] concentration of 1.8*10^-12 M

5 0
3 years ago
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