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2 years ago

Huge loops of plasma erupting from the sun are called.

Chemistry

1 answer:

olasank [31]2 years ago

5 0

Answer:

magnetic Flux ropes

Explanation:

Magnetic flux ropes (also known as coronal loops and solar prominences) sit on the surface of the sun, with matter and energy flowing through them, for hours or days.

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A copper atom has a mass of 1 06 times 10^-22 g and a penny has a mass of 2.5 g. Use this information to answer the questions be

amm1812

Answer:

Mass of 1 mole of copper is 63.83 g.

0.03916 moles of copper atoms have a mass equal to the 2.5 grams of copper penny.

Explanation:

Mass of 1 copper atom,m = $1.06\times 10^{-22} g$

$1 mole = 6.022\times 10^{23} atoms$

Mass of 1 mole of copper :

= $6.022\times 10^{23} atoms\times 1.06\times 10^{-22} g=63.83 g$

Mass of 1 mole of copper = 63.83 g

Mass of copper penny = 2.5 g

Atomic mass of copper = 63.83 g/mol

Moles of copper in 2.5 g of copper penny:

$\frac{2.5 g}{63.83 g/mol}=0.03916 mol$

0.03916 moles of copper atoms have a mass equal to the 2.5 grams of copper penny.

8 0

3 years ago

Explain in your own words the process using the following key words: carbon-di-oxide, water, sugar, oxygen, thylakoid, chloropla

AleksAgata [21]

Answer:

The Photosynthesis process

Explanation:

Plants, algae, and some other organisms can transform the sunlight energy into chemical energy. The photosynthesis process occur thanks to the chloroplasts. The chloroplast is an organelle found in all green plants. Inside of the chloroplast you can find the thylakoids which are arranged in stacks named grana, they have membranes with chloropyll a photosynthetic pigment, also you can find the photosystems, they are functional and structural units of protein complexes. The thylakoids capture the light and allow the reactions to transform CO2. The set of reactions that occurs in the chloroplasts are known as the Calvin cycle.

The general equation of photosynthesis is:

$6 CO_{2} + 6 H_{2} O + Energy -> C_{6} H_{12} 12O_{6} + 6 O_{2}$

6 CO2 + 6 H2O + Energy -> C6H12O6 + 6 O2

Carbon Dioxide + water + Light -> Glucose (sugar) + Oxygen

After, this glucose is transformed into pyruvate, and it allowed the release of denosine triphosphate (ATP) by cellular respiration. The ATP is an organic chemical that is requires for the cell to perform any process (any kind or work).

5 0

4 years ago

The arrows in the image show the direction in which carbon is moving Which process of the carbon cycle is indicated

s344n2d4d5 [400]

The carbon cycle involves the circulation of carbon dioxide (CO2) from the atmosphere into plants and other living organisms; the transfer of carbon from these organisms into other temporary storage pools, living or nonliving, containing organic and inorganic carbon compounds; and the return of CO2 to the atmosphere

8 0

3 years ago

the amount of solar energy reaching 1 m² of earths surface each second is 1.366 x 10^3 joules. if this energy was converted into

Advocard [28]

I think is 6.588579795x10^13 Kg because the equation is E=mc^2 and E is your Joules and c^2= 9x10^16 so m=(c^2)/E

4 0

3 years ago

First-order reaction that results in the destruction of a pollutant has a rate constant of 0.l/day. (a) how many days will it ta

Klio2033 [76]

Rate equation for first order reaction is as follows:

$t=\frac{2.303}{k}log\frac{A_{0}}{A_{t}}$

Here, k is rate constant of the reaction, t is time of the reaction, $A_{0}$ is initial concentration and $A_{t}$ is concentration at time t.

The rate constant of the reaction is $0.1 day^{-1}$ .

(a) Let the initial concentration be 100, If 90% of the chemical is destroyed, the chemical present at time t will be 100-90=10, on putting the values,

$t=\frac{2.303}{k}log\frac{A_{0}}{A_{t}}=\frac{2.303}{0.1 day^{-1}}log\frac{100}{10}=23.03 days$

Thus, time required to destroy 90% of the chemical is 23.03 days.

(b) Let the initial concentration be 100, If 99% of the chemical is destroyed, the chemical present at time t will be 100-99=1, on putting the values,

$t=\frac{2.303}{k}log\frac{A_{0}}{A_{t}}=\frac{2.303}{0.1 day^{-1}}log\frac{100}{1}=46.06 days$

Thus, time required to destroy 99% of the chemical is 46.06 days.

(c) Let the initial concentration be 100, If 99.9% of the chemical is destroyed, the chemical present at time t will be 100-99.9=0.1, on putting the values,

$t=\frac{2.303}{k}log\frac{A_{0}}{A_{t}}=\frac{2.303}{0.1 day^{-1}}log\frac{100}{0.1}=69.09 days$

Thus, time required to destroy 99.9% of the chemical is 69.09 days.

5 0

3 years ago