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3 years ago

Exemplificati solutii in care solventul este gaz

Chemistry

1 answer:

yaroslaw [1]3 years ago

6 0

Answer:

solute (gaz: O,N) + solvent (gaz: Co2) = aer

Sper că vă ajută:)I hope it helps:)

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denpristay [2]

Answer:

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Explanation:

4 0

2 years ago

Read 2 more answers

How is 0.246¯¯¯¯ written as a fraction in simplest form?

KiRa [710]

$0.246 = \dfrac{246}{1000} = \dfrac{246 \div 2}{1000 \div 2} = \dfrac{123}{500}$

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2 years ago

In your own words, describe chromosomes, genes, and DNA.

FinnZ [79.3K]

A gene is the basic unit of heredity, DNA a self replicating material and chromosome a structure of nucleic acids and protein.

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2 years ago

Consider the reaction of diboron trioxide with carbon and chlorine. B2O3 (s) + 3C (s) + 3Cl2 (g) 2BCl3 (g) + 3CO (g) Determine t

Sholpan [36]

Answer:

Limiting reactant = B2O3

Amount of BCl3 formed = 468 g

Explanation:

The given reaction is:

$B2O3 (s) + 3C (s) + 3Cl2 (g) \rightarrow 2BCl3 (g) + 3CO (g)$

In order to identify the limiting reagent calculate the moles of B2O3, C and Cl2. The reagent with the lowest moles is the limiting reactant

$Moles(B2O3)=\frac{Mass(B2O3)}{Mol.wt(B2O3)}=\frac{139g}{69.6g/mol}=1.997moles$

$Moles(C)=\frac{Mass(C)}{At.wt(C)}=\frac{87.8g}{12g/mol}=7.317moles$

$Moles(Cl2)=\frac{Mass(Cl2)}{Mol.wt(Cl2)}=\frac{650g}{70.9g/mol}=9.168moles$

Since the moles of B2O3 < C < Cl2, the limiting reactant is B2O3

Based on the reaction stoichiometry:

1 mole of B2O3 produces 2 moles of BCl3

Hence, the number of moles of BCl3 produced under the experimental conditions = 2*1.997=3.994 moles

$Mass(BCl3)= Moles* Mol.wt = 3.994 moles*117.17g/mol = 468 g$

8 0

2 years ago

A small hole in the wing of a space shuttle requires a 15.9 cm2 patch.

Rzqust [24]

The patch area in square kilometers is 1.59*10⁻⁹ km₂

Why?

This is an unit conversion problem. We have to convert from cm² to km². We can do that by knowing that there are 100 cm in 1 m, and 1000 m in 1 km, so 100000 cm=1km. Knowing that we can apply the following conversion factor:

$15.9 cm^{2} * (\frac{1 km}{100000 cm} )^{2}=0.00000000159 km^{2}$

Now to convert this value to scientific notation, we have to move the decimal point to the right until we get a whole number, and the exponent of the number 10 is going to be the number of spaces we moved to the right (negative), so the final answer is:

$0.00000000159 km^{2}=1.59*10^{-9} km^{2}$

Have a nice day!

#LearnwithBrainly

8 0

3 years ago