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3 years ago

Exemplificati solutii in care solventul este gaz

Chemistry

1 answer:

yaroslaw [1]3 years ago

6 0

Answer:

solute (gaz: O,N) + solvent (gaz: Co2) = aer

Sper că vă ajută:)I hope it helps:)

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The value for Kw is 1.0 x 10-14 at 298K, but this value is temperature dependent. Given what you know about Kw and acid/base che

Papessa [141]

Answer:

The correct answer is option b.

Explanation:

$H_2O\rightleftharpoons H^++OH^-$

The ionic product of water : $K_w$

$K_w=[H^+][OH^-]$

A pure water has equal concentration of hydrogen ions and hydroxide ions, hence neutral.

$K_w=[H^+][H^+]=[H^+]^2$

The ionic product of water at 283 K = $K_w=0.29\times 10^{-14}$

$K_w=[H^+]^2$

$0.29\times 10^{-14}=[H^+]^2$

$[H^+]=5.385\times 10^{-8} M$

The pH of the water at 283 k;

$pH=-\log [H^+]$

$=-\log[5.385\times 10^{-8} M]=7.26$

A pure water has equal concentration of hydrogen ions and hydroxide ions,So water will e neutral at this temperature also.

The correct answer is option b.

4 0

3 years ago

Match each alkane names and structures.

Scilla [17]

First structure is CH₃-CH₃. It is an alkane with two carbon atoms hence it is called ethane.

Second structure is CH₃-CH₂-CH₂-CH₃. It is an alkane with four carbon atoms hence it is called butane.

Third structure is CH₄. It is an alkane with one carbon atom hence it is called methane.

Fourth structure is CH₃-CH₂-CH₃. It is an alkane with three carbon atoms hence it is called propane.

6 0

3 years ago

Jacob has a bucket of ice. He covers the bucket with a lid and sets it in the sun. The ice melts into liquid water. How does the

vekshin1

Assuming that none of the liquid evaporates, the mass of the ice would be the same as the mass of the water because no chemical change occurred, only a phase change occurred.

Hope this helps

4 0

3 years ago

Read 2 more answers

What is the specific heat of copper when heated to 221.32

Dafna1 [17]

Answer:

The specific heat of copper when heated to 221.32 (not listed form of heat measurement) is 221.32 (not listed form of heat measurement).

Explanation:

uh not really sure what else there is here, I may be missing something

5 0

2 years ago

A 3.00 L flexible container holds a sample of hydrogen gas at 153 kPa. If the pressure increases to 203 kPa and the temperature

dybincka [34]

To solve this we assume that the gas is an ideal gas. Then, we can use the ideal gas equation which is expressed as PV = nRT. At a constant temperature and number of moles of the gas the product of PV is equal to some constant. At another set of condition of temperature, the constant is still the same. Calculations are as follows:

P1V1 =P2V2

V2 = P1 V1 / P2

V2 = 153 x 3.00 / 203

3 0

2 years ago