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Aliun [14]
3 years ago
13

Nearsightedness can be corrected by using eyeglass lenses that are

Physics
2 answers:
dusya [7]3 years ago
8 0

Nearsightedness can be corrected by using eyeglass lenses that are  D. concave in shape and cause light rays entering the eyes to diverge.

Mamont248 [21]3 years ago
6 0

Answer:

Concave in shape and cause light rays entering the eyes to diverge.

Explanation:

Nearsightedness is also called myopia. It is a defect in the human eye in which a person is able to see nearby objects clearly but the far objects are seen blurry. In this type of defect, the light is unable to focus on the retina as a result far objects appears blurry.

For the correction of this defect a concave lens is used. It helps to cause light entering eyes to diverge. So, the correct option is (d).

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Which quantity below is a derived quantity?
Reil [10]

By definition, the speed of an object is given by:

v = \frac{dr}{dt}

Where,

dr/dt: derived from the position with respect to time

Therefore, speed has units of length over units of time.

Thus, speed is a derived quantity, since it depends on the value of two other quantities.

Answer:

a derived quantity is:

C. Speed

4 0
3 years ago
Read 2 more answers
Which of the following are thought to be rapidly rotating neutron stars with intense magnetic fields? Choose one answer.a. pulsa
frutty [35]
<h2>Answer: Pulsars</h2>

A <u>pulsar</u> is a neutron star that emits very intense electromagnetic radiation at short and periodic intervals ( rotating really fast) due to its intense magnetic field that induces this emission.  

Nevertheless, it is important to note that all pulsars are neutron stars, but not all neutron stars are pulsars.

Let's clarify:

A neutron star, is the name given to the remains of a supernova. In itself it is the result of the gravitational collapse of a massive supergiant star after exhausting the fuel in its core.  

Neutron stars have a small size for their very high density and they rotate at a huge speed.  

However, the way to know that a pulsar is a neutron star is because of its high rotating speed.  

8 0
3 years ago
Create the following matrix H:
sladkih [1.3K]

Answer:

a) {[1.25  1.5  1.75  2.5  2.75]

    [35  30  25  20  15]  }

b) {[1.5  2  40]

    [1.75  3  35]

    [2.25  2  25]

    [2.75  4  15]}

Explanation:

Matrix H: {[1.25  1.5  1.75  2  2.25  2.5  2.75]

                [1  2  3  1  2  3  4]

                [45  40  35  30  25  20  15]}

Its always important to get the dimensions of your matrix right. "Roman Columns" is the mental heuristic I use since a matrix is defined by its rows first and then its column such that a 2 X 5 matrix has 2 rows and 5 columns.

Next, it helps in the beginning to think of a matrix as a grid, labeling your rows  with letters (A, B, C, ...) and your columns with numbers (1, 2, 3, ...).

For question a, we just want to take the elements A1, A2, A3, A6 and A7 from matrix H and make that the first row of matrix G. And then we will take the elements B3, B4, B5, B6 and B7 from matrix H as our second row in matrix G.

For question b, we will be taking columns from matrix H and making them rows in our matrix K. The second column of H looks like this:

{[1.5]

[2]

[40]}

Transposing this column will make our first row of K look like this:

{[1.5  2  40]}

Repeating for columns 3, 5 and 7 will give us the final matrix K as seen above.

4 0
3 years ago
Earth's neighboring galaxy, the Andromeda Galaxy, is a distance of 2.54×10^7 light-years from Earth. If the lifetime of a human
kupik [55]

Answer:

0.9999986*c

Explanation:

The ship would travel 2.54*10^7 light years, which means that at a speed close to the speed of light the trip would take 2.54*10^7 years from the point of view of an observer on Earth. However from the point of view of a passenger of that ship it will take only 70 years if the speed is close enough to the speed of light.

\Delta t = \Delta t' * \sqrt{1 - (\frac{v}{c})^2}

Where

Δt is the travel time as seen by a passenger

Δt' is the travel time as seen by someone on Earth

v is the speed of the ship

c is the speed of light in vacuum

We can replace the fraction v/c with x

\Delta t = \Delta t' * \sqrt{1 - x^2}

\sqrt{1 - x^2} = \frac{\Delta t}{\Delta t'}

1 - x^2 = (\frac{\Delta t}{\Delta t'})^2

x^2 = 1 - (\frac{\Delta t}{\Delta t'})^2

x = \sqrt{1 - (\frac{\Delta t}{\Delta t'})^2}

x = \sqrt{1 - (\frac{70}{2.54*10^7})^2} = 0.9999986

It would need to travel at 0.9999986*c

5 0
3 years ago
A Is a standard amount like a kilometer or gallon when used to communicate different quantities
Tatiana [17]
I think the missing word you're looking for here is 'unit'. The examples such as kilogram and gallons are all units of measurement. These are standard amounts used for mass, volume, and length. It is especially important to be consistent with this units especially when doing dimensional analysis.
6 0
3 years ago
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