Answer:
Explanation:
Using the equation of motion v = u + at to get the speed at which the object would be travelling.
v is the final speed (in m/s)
u is the initial velocity (in m/s)
a is the acceleration (in m/s²)
t is the time taken (in secs)
Given parameters
u = 0m/s
t = 10s
a = g = 9.8m/s²
Substituting this values into the formula;
v = 0+9.8(10)
v = 0+ 98
v = 98m/s
<em>Hence the rock will be travelling at a speed of 98m/s.</em>
Answer:
Speed at the bottom of the roller coaster = 49.79 m/s
Explanation:
A new ride being built at an amusement park includes a vertical drop of 126.5 meters. Starting from rest, the ride vertically drops that distance before the track curves forward.
We have to find the speed at the bottom.
Here the gravitational energy fully converts to kinetic energy, so we equate it.
Gravitational energy = 
Kinetic energy = 
=
= 2479.4
Velocity, v = 49.79 m/s
Answer:
4.14 m
Explanation:
In the last leg of the journey the ball covers 2 m in 2ms or 0.2 s .
Let in this last leg , u be the initial velocity.
s = ut + 1/2 g t²
2 = .2 u + .5 x 9.8 x .04
u = 9.02 m /s .
Let v be the final velocity in this leg
v² = u² + 2 g s
v² = (9.02)² + 2 x 9.8 x 2
= 81.36 +39.2
v = 10.97 m / s
Now consider the whole height from where the ball dropped . Let it be h.
Initial velocity u = 0
v² = u² +2gh
(10.97 )² = 2 x 9.8 h
h = 6.14 m
Height from window
= 6.14 - 2m
= 4.14 m
