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ss7ja [257]
3 years ago
15

What is antoine lavoisier conservation of mass equation

Physics
1 answer:
ratelena [41]3 years ago
5 0

Answer:

the mass of any one element at the beginning of a reaction will equal the mass of that element at the end of the reaction.

Explanation:

The antoine lavoiser conservation of mass equation can be equal to the mass of the element

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A body which has surface area 5cm² and temperature of 727°C radiates 300J of energy in one minute. Calculate it's emissivity giv
cestrela7 [59]
<h2>Answer: 0.17</h2>

Explanation:

The Stefan-Boltzmann law establishes that a black body (an ideal body that absorbs or emits all the radiation that incides on it) "emits thermal radiation with a total hemispheric emissive power proportional to the fourth power of its temperature":  

P=\sigma A T^{4} (1)  

Where:  

P=300J/min=5J/s=5W is the energy radiated by a blackbody radiator per second, per unit area (in Watts). Knowing 1W=\frac{1Joule}{second}=1\frac{J}{s}

\sigma=5.6703(10)^{-8}\frac{W}{m^{2} K^{4}} is the Stefan-Boltzmann's constant.  

A=5cm^{2}=0.0005m^{2} is the Surface area of the body  

T=727\°C=1000.15K is the effective temperature of the body (its surface absolute temperature) in Kelvin.

However, there is no ideal black body (ideal radiator) although the radiation of stars like our Sun is quite close.  So, in the case of this body, we will use the Stefan-Boltzmann law for real radiator bodies:

P=\sigma A \epsilon T^{4} (2)  

Where \epsilon is the body's emissivity

(the value we want to find)

Isolating \epsilon from (2):

\epsilon=\frac{P}{\sigma A T^{4}} (3)  

Solving:

\epsilon=\frac{5W}{(5.6703(10)^{-8}\frac{W}{m^{2} K^{4}})(0.0005m^{2})(1000.15K)^{4}} (4)  

Finally:

\epsilon=0.17 (5)  This is the body's emissivity

3 0
3 years ago
What is efficiencywhat is the formula of mechanical advantage and velocity ratio of labour ​
sdas [7]

Answer:

Mechanical Advantage = Output Force/Input Force

Velocity Ratio = Driving Gear/Driven Gear

Explanation:

6 0
3 years ago
An car has an acceleration of 8.0 m/s/s. How much time is needed to reach a velocity of 30 m/s from
polet [3.4K]

Answer:

3.75s

Explanation:

a = 8.0 m/s V = 30 m/s U = 0 m/s t = ?

t = V - U/a

t = 30 - 0/8

t = 30/8 = 15/4

t = 3.75s

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3 years ago
A particle of mass 2 g travel a distance of 12 m in a time travel of 2 minute assuming the speed was constant find its kinetic e
balandron [24]

Answer:

0.00001 J

Explanation:

k.e =  \frac{1}{2} m {v}^{2}  \\  =  \frac{1}{2} (0.002) { ( \frac{12}{120} )} ^{2}  \\  = 0.00001j

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