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OLEGan [10]
3 years ago
8

When an object is solely under the influence of conservative forces, the sum of its kinetic and potential energies does not chan

ge. True or False
Physics
1 answer:
MArishka [77]3 years ago
4 0

Answer:

True

Explanation:

- A conservative force is a force whose work done does not depend on the path taken, but only on the final and starting point.

- The mechanical energy of an object is defined as the sum of the kinetic energy (K) and the potential energy (U): E = K + U

- The law of conservation of energy states that, in case only conservative forces are acting on the object, the mechanical energy of the object E is conserved

- In case non-conservative forces are acting on the object, the mechanical energy is no longer constant. An example of non-conservative force is the force of friction: when the force of friction is acting on a car in motion, the car is slowed down by the effect of the force, losing some of its kinetic energy, K. If the car is travelling on a flat road, then its potential energy U does not change: this means that the mechanical energy of the car, E, is decreasing, so it is no longer conserved.

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KatRina [158]

d=? v=2.5 u=0 and t=5 therefore the formula to be used to find the distance my brother covered is d=1/2(v-u)t

d=1/2(2.5-0)5

=6.15m

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3 years ago
As a prank, your friends have kidnapped you in your sleep, and transported you out onto the ice covering a local pond. When you
Ilia_Sergeevich [38]

Answer:

Explained

Explanation:

You should throw your boot in the direction away from the closest shore so that the reaction force is towards the closest shore.

8 0
3 years ago
A 0.150 kg stone rests on a frictionless, horizontal surface. A bullet of mass 9.50 g, traveling horizontally at 380 m/s, strike
Anvisha [2.4K]

Answer:

(a)Magnitude=28.81 m/s

Direction=33.3 degree below the horizontal

(b) No, it is not perfectly elastic collision

Explanation:

We are given that

Mass of stone, M=0.150 kg

Mass of bullet, m=9.50 g=9.50\times 10^{3} kg

Initial speed of bullet, u=380 m/s

Initial speed of stone, U=0

Final speed of bullet, v=250m/s

a. We have to find the magnitude and direction of the velocity of the stone after it is struck.

Using conservation of momentum

mu+ MU=mv+ MV

Substitute the values

9.5\times 10^{-3}\times 380 i+0.150(0)=9.5\times 10^{-3} (250)j+0.150V

3.61i=2.375j+0.150V

3.61 i-2.375j=0.150V

V=\frac{1}{0.150}(3.61 i-2.375j)

V=24.07i-15.83j

Magnitude of velocity of stone

=\sqrt{(24.07)^2+(-15.83)^2}

|V|=28.81 m/s

Hence, the magnitude and direction of the velocity of the stone after it is struck, |V|=28.81 m/s

Direction

\theta=tan^{-1}(\frac{y}{x})

=tan^{-1}(\frac{-15.83}{24.07})

\theta=tan^{-1}(-0.657)

=33.3 degree below the horizontal

(b)

Initial kinetic energy

K_i=\frac{1}{2}mu^2+0=\frac{1}{2}(9.5\times 10^{-3})(380)^2

K_i=685.9 J

Final kinetic energy

K_f=\frac{1}{2}mv^2+\frac{1}{2}MV^2

=\frac{1}{2}(9.5\times 10^{-3})(250)^2+\frac{1}{2}(0.150)(28.81)^2

K_f=359.12 J

Initial kinetic energy is not equal to final kinetic energy. Hence, the collision is not perfectly elastic collision.

5 0
3 years ago
A parallel plate capacitor stores charge, and thus, stores energy in the form of electric potential energy. The total energy sto
DIA [1.3K]

Answer:

The charges on the plates,

Explanation:

A capacitor is an electronic device that can be used for storing of charges. A parallel plate capacitor consists of two plates of equal area separated by a dielectric constant. The energy stored in the capacitor is in the form of potential energy which comes into play during the discharging process of the capacitor.

The energy stored depends majorly on the voltage, area of the plates, distance between the plates and the nature of the dielectric constant of the material between the plates. But it does not depend on the charges on the plates.

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3 years ago
A copper block rests 30.0 cm from the center of a steel turntable. The coefficient of static friction between the block and the
PIT_PIT [208]

Answer:

refer to the above attachment

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2 years ago
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