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sammy [17]
3 years ago
10

This dude was sitting in the chair. Someone pulls the chair out from under him. He does not move in the direction of the chair.

He simply falls to the ground in the same spot he was sitting. This shows inertia because:
Physics
1 answer:
Oksanka [162]3 years ago
8 0

Answer:

This shows inertia because inertia is an object's resistance to change in motion. When the person (imma call them a she) who pulled the chair from under the guy did that, the chair was the one affected by the force of the girl, not the guy. The guy continued heading in the direction he was originally going, which was down.

At least, that's about how I would answer this question.

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A satellite moves in a circular orbit at a constant speed v0 around Earth at a distance R from its center. The force exerted on
postnew [5]

Answer:

vT = v0/3

Explanation:

The gravitational force on the satellite with speed v0 at distance R is F = GMm/R². This is also equal to the centripetal force on the satellite F' = m(v0)²/R

Since F = F0 = F'

GMm/R² = m(v0)²/R

GM = (v0)²R  (1)

Also, he gravitational force on the satellite with speed vT at distance 3R is F1 = GMm/(3R)² = GMm/27R². This is also equal to the centripetal force on the satellite at 3R is F" = m(vT)²/3R

Since F1 = F'

GMm/27R² = m(vT)²/3R

GM = 27(vT)²R/3

GM = 9(vT)²R (2)

Equating (1) and (2),

(v0)²R = 9(vT)²R

dividing through by R, we have

9(vT)² = (v0)²

dividing through by 9, we have

(vT)² = (v0)²/9

taking square-root of both sides,

vT = v0/3

6 0
3 years ago
Let's say you are on the third story of an apartment building that has a swimming pool. For some insane reason you think it is a
labwork [276]

Answer:

To make it into the pool you must run and jump at

\displaystyle v_o=x.\sqrt{\frac{g}{2y}}

Explanation:

Horizontal Launch

When an object is thrown with a specified initial speed in the horizontal direction, it describes a curved path that finishes when it hits the ground level after traveling certain horizontal distance x and a vertical height y from the launching point. The horizontal speed is always constant and the vertical speed increases due to the effect of gravity. It can be found that the horizontal distance reached by the object when launched at an initial speed  in a given time t is

x=v_o.t

And the vertical distance is

\displaystyle y=\frac{g.t^2}{2}

If t is the total flight time, then x and y are maximum and we can find a relation between them. Solving for t in the first equation

\displaystyle t=\frac{x}{v_o}

Substituting in the second equation

\displaystyle y=\frac{g}{2}\left ( \frac{x}{v_o}\right )^2

Rearranging

\displaystyle \left ( \frac{v_o}{x}\right )^2=\frac{g}{2y}

Solving for v_o

\displaystyle v_o=x.\sqrt{\frac{g}{2y}}

There are many applications for the horizontal launch. One common situation is when someone wants to drop something on certain terrain at a specific approximate point when traveling in a plane at a given height. Once the object is left fall, it has the same speed as the plane, so the plane speed can be estimated to make the best possible launch, or given that speed, we can know in advance where the object will reach ground level

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By what factor will the electric force between two charged objects change if the charge on both objects is quadrupled
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D.16 with working shown below with respect to Coulomb’s law.
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4 years ago
What feelings do learned helplessness and depression have in common?
8_murik_8 [283]

Answer:

Learned helplessness can have a profound impact on mental health and well-being. People who experience learned helplessness are also likely to experience symptoms of depression, elevated stress levels, and less motivation to take care of their physical health. Not everyone responds to experiences the same way.

Explanation:

Brainlist will be very accepted ;D *wink*

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Find A and B <br> I need help like asap so pleasee help
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Answer:

I don't understand?

Explanation:

Could you please elaborate?

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