A 30 kg student drops down from the monkey bars. The acceleration due to gravity is -9.8 m/s^2. Neglecting air drag, what is the
1 answer:
The net force on the student is A) -294 N
Explanation:
Neglecting air resistance, there is only one force acting on the student: the force of gravity, which is given by
where
m is the mass of the student
g is the acceleration of gravity
In this problem, we have:
m = 30 kg is the mass of the student
is the acceleration of gravity, where the negative sign means the direction is downward
Substituting, we find the force of gravity on the student:
And since this is the only force acting on the student, it is also the net force on him.
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<h2>Answer: 277.777 m</h2>
Explanation:
The situation described here is parabolic movement. However, as we are told that the rock was<u> projected upward from the surface</u>, we will only use the equations related to the Y axis.
In this sense, the movement equations in the Y axis are:
(1)
(2)
Where:
is the rock's final position
is the rock's initial position
is the rock's initial velocity
is the final velocity
is the time the parabolic movement lasts
is the acceleration due to gravity at the surface of the moon
As we know , equation (2) is rewritten as:
(3)
On the other hand, the maximum height is accomplished when :
(4)
(5)
Finding :
(6)
Substituting (6) in (3):
(7)
(8) Now we can calculate the maximum height of the rock
(9)
Finally: