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Paladinen [302]
3 years ago
6

A 30 kg student drops down from the monkey bars. The acceleration due to gravity is -9.8 m/s^2. Neglecting air drag, what is the

net force acting the on student?
A)-294 N
B)-3 N
C)0.3 N
D)294 N
Physics
1 answer:
Sholpan [36]3 years ago
8 0

The net force on the student is A) -294 N

Explanation:

Neglecting air resistance, there is only one force acting on the student: the force of gravity, which is given by

F=mg

where

m is the mass of the student

g is the acceleration of gravity

In this problem, we have:

m = 30 kg is the mass of the student

g=-9.8 m/s^2 is the acceleration of gravity, where the negative sign means the direction is downward

Substituting, we find the force of gravity on the student:

F=(30)(-9.8)=-294 N

And since this is the only force acting on the student, it is also the net force on him.

Learn more about gravitational force:

brainly.com/question/1724648

brainly.com/question/12785992

#LearnwithBrainly

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The work done in the isothermal process is 10 joule.

We need to know about the isotherm process to solve this problem. The isotherm process can be described as a process where the initial temperature system will be the same as the final temperature. Hence, the internal energy change will be zero.

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Hence,

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Answer:

Explanation:

From the given information:

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