(yz)log y - logz . (zx)log 2 - log x- (xv) log x-logy = 1
1 answer:
Answer:
yz)
log(
z
y
)
.(zx)
log(
x
z
)
.(xy)
log(
y
x
)
=
⎣
⎢
⎢
⎡
x
log(
x
z
)
.x
log(
y
x
)
⎦
⎥
⎥
⎤
×
⎣
⎢
⎢
⎡
y
log(
z
y
)
.y
log(
y
x
)
⎦
⎥
⎥
⎤
×
⎣
⎢
⎡
z
log(
z
y
)
.z
log(
x
z
)
⎦
⎥
⎤
=x
log(
y
z
)
.y
log(
z
x
)
.z
log(
x
y
)
=(x
logz−logy
).(y
logx−logz
).(z
logy−logx
)
=
x
logy
x
logz
.
y
logz
y
logx
.
z
logx
z
logy
=
y
logx
x
logz
.
z
logy
y
logx
.
x
logz
z
logy
=1
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36 3/4 = 36.75
36 3/8 = 36.375
37 1/2 = 37.5
36 5/8 = 36.625
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(110.625 + z) / 4 = 36.625
110.625 + z = 36.625 * 4
110.625 + z = 146.5
z = 146.5 - 110.625
z = 35.875 or 35 7/8 <===
Answer
6.9473
Step-by-step explanation:
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